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max2010maxim [7]
3 years ago
14

Help me plzzz solve for x

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

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The answer is A. About 1  1/2. Hope it helps u!!! :)

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3 years ago
The circumference of a
timama [110]

9514 1404 393

Answer:

  • 160,000 m²
  • 16 ha

Step-by-step explanation:

The side length of a square is 1/4 of the perimeter, so the side length of the square orchard is (1600 m)/4 = 400 m.

The area of a square is the square of the side length, so the area of the orchard is (400 m)² = 160,000 m².

A hectare is 10,000 m², so the area of the orchard in hectares is ...

  16·(10,000 m²) = 16 ha

3 0
3 years ago
What is the gum of 70 and 50
Scorpion4ik [409]

Answer:

120 ? what this supposed to be about ? is it to estimate or subtract? does this have mutiple choices?  and what gum are their referring too ? the gum you chew or in your teeth?

6 0
3 years ago
Solve (x + 3 &lt; 5) U (x - 7 &gt; 1).
ale4655 [162]

Answer:

{ x | x < 2 or x > 8}

Step-by-step explanation:

Given the expression

(x + 3 < 5) U (x - 7 > 1).

Solve x+3 < 5

Subtract 3 from both sides

x+3 - 3 < 5-3

x < 2

For x - 7 > 1

Add 7 to both sides

x-7+7 > 1 + 7

x > 8

Hence the union of both is { x | x < 2 or x > 8}

4 0
3 years ago
Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

V_{flask}=V_{sphere}+V_{cylinder}.

Use following formulas to determine volumes of sphere and cylinder:

V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

  • V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;
  • V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;
  • V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.

Then

\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.

Answer 2: correct choice is D.


8 0
4 years ago
Read 2 more answers
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