I really need help doing this I think its

Which expression is equivalent to -2v+(-4)+(-3v)? A -5 B 7v C -6v+5 D -5v+ 4

inessss [21]

Answer:

-5v+4

Step-by-step explanation:

Remove the parentheses and combine the like terms:

-2v + (-4) + 8 + (-3v)

-2v -4 + 8 -3v [Remove parentheses]

-5v +4 [Combine like terms]

-5v +4

3 0

2 years ago

Please help quick! Proportions & Graphs

Triss [41]

Answer:

1. No

2. No

3. Yes

4. No

Step-by-step explanation:

The first one isn't proportional because it doesn't start at 0

The second one isn't proportional because there isn't a pattern between the coordinates

The 3rd one is a proportional relationship because it starts at 0 and there is an equal amount of space between each coordinate and there is evidentially a pattern.

Finally, the 4th one isn't proportional because the last coordinate doesn't correspond w/ the others

Plz mark me brainliest if correct :)

3 0

3 years ago

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

$AC=5\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=4+3+5=12\ units$

6 0

3 years ago

Solve the system of equations: X+y+z=5 -3x-4y+4z=15 2x-y-4z=-8

atroni [7]

Answer:

(x, y, z) = (3, -2, 4)

Step-by-step explanation:

The attachment shows a solution using a graphing calculator where the first equation is solved for z, and that expression is substituted into each of the other two equations. The solution to that system is (x, y) = (3, -2). Using these values in the expression for z, we find ...

z = 5 -(3 +(-2)) = 4

The solution is (x, y, z) = (3, -2, 4).

__

Your graphing calculator and/or online tools can give you the reduced row echelon form of the augmented matrix representing the system:

$\left[\begin{array}{ccc|c}1&1&1&5\\-3&-4&4&15\\2&-1&-4&-8\end{array}\right]$

__

If you're solving by hand, you can do the substitution described above to eliminate z from one equation. You can eliminate z from another equation by adding the last two:

-3x -4y +4(5 -x -y) = 15 ⇒ -7x -8y = -5

(-3x -4y +4z) +(2x -y -4z) = (15) +(-8) ⇒ -x -5y = 7

This pair of equations can be solved for x and y in any of the usual ways. Using the second equation to substitute for x, for example, gives you ...

-7(-5y -7) -8y = -5 ⇒ 27y = -54 ⇒ y = -2

x = -5(-2) -7 = 3

z = 5 -(3) -(-2) = 4

_____

Additional comment

If all that is needed is a solution, we prefer a graphical or matrix approach. These take about the same amount of time. Both require a little additional effort to determine exact values when the solutions are not integers.

6 0

2 years ago

I need help with this problem

-BARSIC- [3]

Regular is
$97.99 after sale price is 83.30
97.99- 83.30= 14.69 is the discount
You can do it same way with B C and D

6 0

3 years ago