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3 years ago

What is the gum of 70 and 50

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

6 0

Answer:

120 ? what this supposed to be about ? is it to estimate or subtract? does this have mutiple choices? and what gum are their referring too ? the gum you chew or in your teeth?

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Ok, I am so sorry ,I rlly don't understand any of these things , can y'all help me with

melomori [17]

Answer:

x is 2.88 which can be rounded up to 2.9

Step-by-step explanation:

Subtract 2/3x from 5x.

Add 1/2 to 12.

Simplify and put into calculator (y=) to double check.

3 0

3 years ago

Adding and Subtracting with Rational Numbers

Pavel [41]

Answer:

-4.6 ft

Step-by-step explanation:

We need to learn to extract only the necessary information to answer question. The surf shop and the restaurant is extra information.

Monday 1 pm 2.2 ft

Monday 7 pm - 2.4 ft

Net change

-2.4 ft - 2.2 ft = -4.6 ft

The ocean went down 4.6 ft from 1 pm to 7 pm on Monday

4 0

3 years ago

Jose bought a plant. The height, h, of the plant is 2 feet. He noticed that every month, m,

Kipish [7]

Answer:

the answer is h=0.5m+2 I think

6 0

3 years ago

What is the solution to the equation 93x ≈ 7?

s344n2d4d5 [400]

Well, I do not know if you mean 93x = 7 or 9^3x = 7.
So, I will provide the solution for both cases.

In case of 93x = 7:
This case is simple, all you have to do is isolate the x. You need to get rid of the coefficient which is 93. You can simply do this by dividing both sides of the equation by 93 as follows:
93x = 7
93x / 93 = 7/93
x = 7/93

In case of 9^3x = 7:
Now, we need to get rid of the power. The only function that can do this is the log function.
So, we will start by taking log base 10 for both sides of the equation as follows:
9^3x = 7
log(9^3x) = log(7)
This will give:
3x * log(9) = log(7)
Now, the final step is to isolate the x as we did before. To do this, we will need to get rid of 3log(9). This can be done by dividing both sides of the equation by 3log(9) as follows:
3x * log(9) / 3log(9) = log(7) / 3log(9)
This will give us:
x = log(7) / 3log(9) = 0.2952

Hope this helps :)

5 0

4 years ago

Need help please its Calculus. Ill give the 5 stars as well.

algol13

Answer:

$\displaystyle y = 2e^\bigg{\frac{x^3}{3}} + 1$

General Formulas and Concepts:

Pre-Algebra

Order of Operations
Equality Properties

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Algebra II

Natural logarithms ln and Euler's number e

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Slope Fields

Separation of Variables

Solving Differentials

Integrals

Antiderivatives

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Logarithmic Integration: $\displaystyle \int {\frac{1}{u}} \, dx = ln|u| + C$

Step-by-step explanation:

*Note:

When solving differential equations in slope fields, disregard the integration constant C for variable y.

Step 1: Define

$\displaystyle \frac{dy}{dx} = x^2(y - 1)$

$\displaystyle f(0) = 3$

Step 2: Rewrite

Separation of Variables. Get differential equation to a form where we can integrate both sides and rewrite Leibniz Notation.

[Separation of Variables] Rewrite Leibniz Notation: $\displaystyle dy = x^2(y - 1) \ dx$
[Separation of Variables] Isolate y's together: $\displaystyle \frac{1}{y - 1} \ dy = x^2 \ dx$

Step 3: Find General Solution Pt. 1

[Differential] Integrate both sides: $\displaystyle \int {\frac{1}{y - 1}} \, dy = \int {x^2} \, dx$
[dx Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle \int {\frac{1}{y - 1}} \, dy = \frac{x^3}{3} + C$

Step 4: Find General Solution Pt. 2

Identify variables for u-substitution for dy.

Set: $\displaystyle u = y - 1$
Differentiate [Basic Power Rule]: $\displaystyle du = dy$

Step 5: Find General Solution Pt. 3

[dy Integral] U-Substitution: $\displaystyle \int {\frac{1}{u}} \, du = \frac{x^3}{3} + C$
[dy Integral] Integrate [Logarithmic Integration]: $\displaystyle ln|u| = \frac{x^3}{3} + C$
[Equality Property] e both sides: $\displaystyle e^\bigg{ln|u|} = e^\bigg{\frac{x^3}{3} + C}$
Simplify: $\displaystyle |u| = Ce^\bigg{\frac{x^3}{3}}$
Rewrite: $\displaystyle u = \pm Ce^\bigg{\frac{x^3}{3}}$
Back-Substitute: $\displaystyle y - 1 = \pm Ce^\bigg{\frac{x^3}{3}}$
[Equality Property] Isolate y: $\displaystyle y = \pm Ce^\bigg{\frac{x^3}{3}} + 1$

General Form: $\displaystyle y = \pm Ce^\bigg{\frac{x^3}{3}} + 1$

Step 6: Find Particular Solution

Substitute in function values [General Form]: $\displaystyle 3 = \pm Ce^\bigg{\frac{0^3}{3}} + 1$
Simplify: $\displaystyle 3 = \pm C + 1$
[Equality Property] Isolate C: $\displaystyle 2 = \pm C$
Rewrite: $\displaystyle C = 2$
Substitute in C [General Form]: $\displaystyle y = 2e^\bigg{\frac{x^3}{3}} + 1$

∴ our particular solution is $\displaystyle y = 2e^\bigg{\frac{x^3}{3}} + 1$ .

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentials and Slope Fields

Book: College Calculus 10e

6 0

3 years ago