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USPshnik [31]
4 years ago
13

Solve: Square root of 108 + square root of 3

Mathematics
1 answer:
Gre4nikov [31]4 years ago
5 0

Answer:

12.124355653

Step-by-step explanation:

don't know if you need to round but square root of 108 is 10.3923048454 and square root of 3 is 1.73205080757

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Prove that root3 (cosec (20))-sec (20)=4
Tems11 [23]
Root 3 /sin 20 - 1/cos 20

= (root3 cos 20 - sin 20 )/ (sin 20 cos 20)
(multiplying and dividing by 2)
=  2* (root3/2 cos 20 -1/2 sin 20)/ (sin 20 cos 20)

now sin 20 cos 20  = (2 sin 20 cos 20)/2 = (sin 40)/2
and writing root3/2 = sin 60, 1/2 = cos 60

= 2* (sin 60 cos 20 - cos 60 sin 20)/ (sin 40)/2

= 4* (sin (60-20))/sin 40

= 4* (sin 40)/sin 40
=4

Ask if any doubt in any step :)
7 0
3 years ago
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What is the GCF of the two terms in the expression 15x - 25
Pepsi [2]
5 is the GCF because 5 divided by 15 is 3 and 25 divided by 5 is 5.
8 0
3 years ago
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Find the range, mean, and standard deviation of the data set (3, 6, 9, 11, 15, 16) The range is 13 (Type a whole number.) The me
iris [78.8K]

Answer: The range is 13.  The mean is 10. The standard deviation is 4.62 .

Step-by-step explanation:

The given data : 3, 6, 9, 11, 15, 16

Total number of data values : n = 6

The mean of data is given by :-

\overline{x}=\dfrac{\sum^6_{i=1}x_i}{n}\\\\\Rightarrow\overline{x}=\dfrac{60}{6}=10

The standard deviation is given by :-

\sqrt{\dfrac{1}{n}(\sum^6_{i=1}(x_i-\overline{x})^2)}\\\\=\sqrt{\dfrac{1}{6}(\sum^6_{i=1}(x_i-10)^2)}\\\\=\sqrt{\dfrac{1}{6}\times(49+16+1+1+25+36)}=4.61880215352\approx4.62

The range of the data : Maximum value -Minimum value

=16-3=13

6 0
3 years ago
$500 shared in ratio 2:3:9
RideAnS [48]
2:3:9......added together = 14

2/14 (500) = 1000/14 = 71.43
3/14 (500) = 1500/14 = 107.14
9/14 (500) = 4500/14 = 321.43
6 0
3 years ago
Please help me asap​
schepotkina [342]
3.) A *the first one*
4.) C *the last one*
6 0
3 years ago
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