What is 54% as a fraction?
2 answers:
You might be interested in
Answer:
- The scale factor is one-half
- The perimeter of the model is the product of the scale factor and the perimeter of the original rectangle
-The area of the reduced figure is (1/2)^2 = 1/4 times the area of the original figure
Step-by-step explanation:
The ratio of the length of the original rectangle to that of the reduced rectangle is 6 to 3, or a factor of 1/2. The ratio of the width of the original rectangle to that of the reduced rectangle is 2 to 1, or, again, a factor of 1/2. So, because this ratio of 1/2 is constant, we know the total scale factor is 1/2, making B correct.
The perimeter of a rectangle is: , where l is the length and w is the width. The perimeter of the reduced figure is: P = 2 * 3 + 2 * 1 = 6 + 2 = 8 units. The perimeter of the original figure is: P = 2 * 6 + 2 * 2 = 12 + 4 = 16 units.
Notice that 16 * (1/2) = 8, which means that the perimeter of the scale-factored, reduced rectangle is "the product of the scale factor (which is 1/2) and the perimeter of the original rectangle (which is 16)". So, C is correct.
The area of a rectangle is: , where l is the length and w is the width. The area of the reduced figure is: A = 3 * 1 = 3 units squared. The area of the original figure is: A = 6 * 2 = 12 units squared.
Notice that 12 * (1/4) = 3, which means that E is correct, but D is wrong.
Hope this helps!
The <u>correct answer</u> is:
6 mph.
Explanation:
We will use the formula d = rt for this, where d is <u>distance</u>, r is <u>rate</u>, and t is <u>time</u>.
We know that the time for both distances is the same; this means we want to isolate t in our formula. To do this, we will cancel r by dividing both sides:
d/r = rt/r
d/r = t
We will write an expression for the time upstream, an expression for the time downstream, and set them equal.
For the time upstream, the distance is 6 and the rate is 24-x; this gives us
For the time downstream, the distance is 10 and the rate is 24+x; this gives us
Together, these give us the equation
We cross-multiply to solve this:
6(24+x) = 10(24-x)
Using the distributive property, we have
6*24 + 6*x = 10*24 - 10*x
144+6x = 240-10x
Adding 10x to each side,
144+6x+10x = 240-10x+10x
144+16x = 240
Subtract 144 from each side:
144+16x-144 = 240-144
16x = 96
Divide both sides by 16:
16x/16 = 96/16
x = 6
6 mph.
Explanation:
We will use the formula d = rt for this, where d is <u>distance</u>, r is <u>rate</u>, and t is <u>time</u>.
We know that the time for both distances is the same; this means we want to isolate t in our formula. To do this, we will cancel r by dividing both sides:
d/r = rt/r
d/r = t
We will write an expression for the time upstream, an expression for the time downstream, and set them equal.
For the time upstream, the distance is 6 and the rate is 24-x; this gives us
For the time downstream, the distance is 10 and the rate is 24+x; this gives us
Together, these give us the equation
We cross-multiply to solve this:
6(24+x) = 10(24-x)
Using the distributive property, we have
6*24 + 6*x = 10*24 - 10*x
144+6x = 240-10x
Adding 10x to each side,
144+6x+10x = 240-10x+10x
144+16x = 240
Subtract 144 from each side:
144+16x-144 = 240-144
16x = 96
Divide both sides by 16:
16x/16 = 96/16
x = 6