-5
a^2-25=0
a^2=25
take the square root of both sides
a=5, and -5
Option B:
sin x = 1 is the equation represented by the intersection of the graph.
Solution:
The graph lies between -1 and 1 in y-axis.
x-axis of the graph is all real numbers.
The graph oscillates between -1 and 1 and a shape that repeats itself every 2π units.
That is the domain of the graph is all real numbers.
The range of the graph is [-1, 1].
It clearly shows that, it is the graph of sinx = 1.
Hence sin x = 1 is the equation represented by the intersection of the graph.
Option B is the correct answer.
Answer:
x= -8
collect like term than divide both sides
6x-4x = -20+4
2x= -20+4
2x=-16
x= -8
Answer:
the answer for your question is b
Answer:
y = x + 4
Step-by-step explanation:
Since x > 5, x-3 > 0, x + 2 > 0 and x - 5 > 0
So Ix - 3I = x - 3, Ix + 2I = x + 2 and x - 5 = x - 5
Therefore, y = x - 3 + x + 2 - x + 5
y = x + 4
