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Fantom [35]
3 years ago
8

If RS=ST then point S is called the midpoint of RT. Always. Sometimes. Never.

Mathematics
2 answers:
Drupady [299]3 years ago
8 0
It's not stated if point S is on line RT. So it seems like the answer is "Sometimes". If the teacher tells you that point S is on line RT, then the answer will be "Always". This is because S divides RT into two parts RS and ST. Both of those parts are congruent. 
a_sh-v [17]3 years ago
4 0

Answer:

always is right

Step-by-step explanation:

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If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3
horrorfan [7]

Answer:  The correct option is (B) 24 : 25.

Step-by-step explanation:  Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Therefore, the ratio of the area of R to the area of S is

\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0
3 years ago
What is the solution to the system of equations?<br><br> y = –5x + 3<br><br> y = 1
Alinara [238K]
Ok so we know that y=1 so we can simply sub in the value of y into the equation :

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7 0
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3 0
3 years ago
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