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4 years ago

The sum of two consecutive odd integers is 236. What is the smaller integer?

2 answers:

5 0

HEY there,

236/2=117

117 enn odd number

117+117=236

1,3,7 are odd number so

hope this helped you

Plz mark brainliest if you want (;

Nonamiya [84]4 years ago

4 0

The answer is 117. Hope this helps and good job :)

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A box has dimensions of 14 inches long, 1.5 feet wide, and 7 inches high. What is the volume of the box? The formula for the vol

goblinko [34]

convert the feet to inches

1 foot = 12 inches

so 1.5 ft =1.5*12 = 18 inches

now multiply all 3

14*18*7 = 1764 cubic inches

8 0

3 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

3 years ago

The height, h, in meters above ground, of a projectile at any time, t, in seconds, after the launch is defined by the

Jlenok [28]

Answer:

the projectile reached a maximum height of 27.6 meters in 2.4 seconds and it took 5.0 seconds for it to hit the ground

Step-by-step explanation:

to find the vertex you can find the axis of symmetry first

that equation is -b/2a

-19/-8 = 2.375

then you take this and plug it in

-4(2.375)^2 + 19*2.375 + 5

that gives you 27.5625

then you have to find when it hits the ground

you can factor to find this out

-4t^2 + 19t + 5

4t^2 - 19t - 5

4t^2 + t - 20t - 5

t(4t + 1) -5(4t +1)

(t - 5)(4t + 1)

t = {5, -1/4}

we can only take positive time so it took 5 seconds

the answer is the second one

5 0

2 years ago

If triangle ABC is defined by the coordinates A(-4, -4), B(2, -2), C(0, 4) is dilated by a scale factor of 1 2 , with resulting

PtichkaEL [24]

Answer:

the origin, (0, 0)

Step-by-step explanation:

The coordinates of A' are 1/2 those of A, meaning each has been multiplied by the scale factor 1/2. When the dilated points are all the original points multiplied by the scale factor, the center of dilation is the origin.

_____

For center of dilation Q, the image of a point A after dilation by a factor of k is ...

A' = kA + (k-1)Q

Then for points A, A', and dilation factor k, the center of dilation can be found to be ...

(A' -kA)/(k-1) = Q

Here, that is ...

Q = ((-2, -2) -(1/2)(-4, -4))/(1/2 -1) = (0, 0)/(-1/2)

Q = (0, 0)

7 0

3 years ago

Rovide an appropriate response.4) assume that adults have iq scores that are normally distributed with a mean of 100 and a stand

Tcecarenko [31]

9484 hope i helped u

6 0

4 years ago