Because change in y for the rise is if it goes up or down and change in x for the run to see if it goes left or right
The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
4
Step-by-step explanation:
If the shapes are similar we can use the side length proportion to find the value of x:
7/91 = x/52 cross multiply expressions
91x = 364 divide both sides by 91
x = 4
Answer:
y = 460 miles per hr
x = 500 miles per hr
Step-by-step explanation:
Let the planes be X any
Let their speeds be xmiles/hr and ymiles/hr respectively
x = y + 40 (assuming X is faster by 40miles/hr)
Distance travelled by X to meet Y = 0.75x
Distance travelled by Y to meet X = 0.75y
0.75x + 0.75y = 720 --------1
Put x = y + 40 in eqn 1
0.75(y+40) + 0.75y = 720
0.75y + 30 + 0.75y= 720
1.5y = 690
y = 460 miles per hr
x = 460 +40
= 500 miles per hr
Answer:
1. 100 1. 150 1. 1
2.45 2. 800
Step-by-step explanation:
1. 25% * 400 = 0.25 * 400 =
* 400 = 100
2. 50% * 90 = 45
1. 75% * 200 = 0.75 * 200 = 3/4 * 200 = 150
2. 10% * 8000 = 0.1 * 8000 = 800
1. 5% * 20 = 0.05 * 20 = 1