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ikadub [295]
2 years ago
15

Solve (x^3-4x)(2x^2-3x)​

Mathematics
1 answer:
nata0808 [166]2 years ago
5 0

Answer:

= x^2 ( 2x^3- 3x^2 - 8x + 12)

Step-by-step explanation:

(x^3-4x) (2x^2-3x)

= x^3(2x^2-3x) -4x(2x^2-3x)

= 2x^5-3x^4-8x^3+12x^2

= x^2 ( 2x^3- 3x^2 - 8x + 12)

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kherson [118]
<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
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f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
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2 years ago
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a group of students arrange a picnic each student contributed rupees 61 1 upon 2 the total contribution was rupees 676 1 upon 2
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(i hope it is correct answer. pls mark as brainliest)

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