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ikadub [295]
3 years ago
15

Solve (x^3-4x)(2x^2-3x)​

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

= x^2 ( 2x^3- 3x^2 - 8x + 12)

Step-by-step explanation:

(x^3-4x) (2x^2-3x)

= x^3(2x^2-3x) -4x(2x^2-3x)

= 2x^5-3x^4-8x^3+12x^2

= x^2 ( 2x^3- 3x^2 - 8x + 12)

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Denise bought a t-shirt at the sale price of $25.the original cost of the t-shirt was $40.what percent represents the discount t
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A company produces a certain product, and each unit of this product may have 3 different types of defects. Let Di, D2,Ds represe
Stella [2.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) 0.88

b) 0.02

c) 0.01

d) 0.99

Step-by-step explanation:

Step one: State the given parameters

            P(D_{1} ) = 0.12                                   P(D_{2} ) = 0.07

           P(D_{3} ) = 0.05                                    P (D_{1} U D_{2} ) = 0.13

          P(D_{1}n D_{2}n D_{3}) = 0.01                        P(D_{1} U D_{3}) = 0.14

Step 2 : Obtain the probability that a unit does not have a type 1 defect

         P(\frac{}{D_{1} }) =  1 -P(D_{1} )

                    = 1 - 0.12

                    = 0.88  

Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?

          The probability of the unit having both type 2 and type 3 defect is denoted as P(D_{2} n D_{3} )

   This is calculated as

                    P(D_{2}n D_{3}) =P(D_{2} ) + P(D_{3}) - P(D_{2} U D_{3})\\\\                          = 0.07 + 0,05 - 0.13

                    =   0.02

Therefore P(D_{2} n D_{3} ) = 0.02

Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect

                  Let P(\frac{}{D_{1}} n D_{2} n D_{3} ) denote the  probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.

This can be calculated as follows :

                      P(\frac{}{D_{1}} n D_{2} n D_{3} ) = P(D_{2} n D_{3}) - P(D_{1} n D_{2}nD_{3})

                                               =   0.02 - 0.01

                                               =  0.01

Step 4 : Obtain the probability that a unit has at most two defects

               P(at most 2 defects)  = 1 - P(all three defects)

                                                  = 1- P(D_{1} n D_{2}nD_{3})

                                                  =  1 - 0.01

                                                  = 0.99

7 0
3 years ago
Help me pleaseeeeeeeeeeeeeeee
SVETLANKA909090 [29]

Answer:

452.39

Step-by-step explanation:

The question is asking for the area of the pool, so use the circle area formula, which is A=\pi r^{2}. In the formula, A is the area and r is the radius. The question gives us the diameter, so divide that by 2 to get the radius. Therefore the equation is A=\pi 12^{2}, then solve to get 452.39.

8 0
3 years ago
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