2 years ago

Solve (x^3-4x)(2x^2-3x)

Mathematics

1 answer:

nata0808 [166]2 years ago

5 0

Answer:

= x^2 ( 2x^3- 3x^2 - 8x + 12)

Step-by-step explanation:

(x^3-4x) (2x^2-3x)

= x^3(2x^2-3x) -4x(2x^2-3x)

= 2x^5-3x^4-8x^3+12x^2

= x^2 ( 2x^3- 3x^2 - 8x + 12)

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2 years ago

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

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Answer:

Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

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$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\$

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1 year ago

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Leokris [45]

Answer:

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~Hope this helps~

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2 years ago

Solve (x^3-4x)(2x^2-3x)​

Solve (x^3-4x)(2x^2-3x)