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topjm [15]
3 years ago
9

Two planes that are traveling toward each other are 720 miles apart. One plane is traveling 40 miles per hour faster than the ot

her. The planes pass after 0.75 hours. How fast is each plane traveling?
Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:

y = 460 miles per hr

x = 500 miles per hr

Step-by-step explanation:

Let the planes be X any

Let their speeds be xmiles/hr and ymiles/hr respectively

x = y + 40 (assuming X is faster by 40miles/hr)

Distance travelled by X to meet Y = 0.75x

Distance travelled by Y to meet X = 0.75y

0.75x + 0.75y = 720 --------1

Put x = y + 40 in eqn 1

0.75(y+40) + 0.75y = 720

0.75y + 30 + 0.75y= 720

1.5y = 690

y = 460 miles per hr

x = 460 +40

= 500 miles per hr

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7 0
3 years ago
Số tiếp theo (next number?): 25 50 99 196 388
Delvig [45]

Answer:

The correct answer is - 768.

Step-by-step explanation:

The given question is based on a specific pattern present in between the numbers in the given series -

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to find - next number in series

let us find the relation between the initial two number:

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relation between 2nd and 3rd number:

50 - 99, here 99 is two times of 50 minus 1 or (x*2-1)

relation between 3rd and 4th number:

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relation between 4th and 5th number:

196 - 388, here 388 is the two times of 196 minus 4 or (x*2-4)

So on this pattern, the next number would be = x*2-8

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5 0
3 years ago
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3 0
3 years ago
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Answer:

https://ohsrehak.weebly.com/uploads/5/4/6/9/54699399/5-1_bisectors_of_triangles_solutions.pdf   paste the click

Step-by-step explanation:

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