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topjm [15]
3 years ago
9

Two planes that are traveling toward each other are 720 miles apart. One plane is traveling 40 miles per hour faster than the ot

her. The planes pass after 0.75 hours. How fast is each plane traveling?
Mathematics
1 answer:
natali 33 [55]3 years ago
7 0

Answer:

y = 460 miles per hr

x = 500 miles per hr

Step-by-step explanation:

Let the planes be X any

Let their speeds be xmiles/hr and ymiles/hr respectively

x = y + 40 (assuming X is faster by 40miles/hr)

Distance travelled by X to meet Y = 0.75x

Distance travelled by Y to meet X = 0.75y

0.75x + 0.75y = 720 --------1

Put x = y + 40 in eqn 1

0.75(y+40) + 0.75y = 720

0.75y + 30 + 0.75y= 720

1.5y = 690

y = 460 miles per hr

x = 460 +40

= 500 miles per hr

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4 0
3 years ago
Solve for x in the equation 6(–5)=54 6 ( x – 5 ) = 54 .
Ad libitum [116K]

Answer:

x = 14

Step-by-step explanation:

Let's solve your equation step-by-step.

6(x − 5) = 54

Step 1: Simplify both sides of the equation.

6(x − 5) = 54

(6)(x) + (6)(−5) = 54(Distribute)

6x + − 30 = 54

6x − 30 = 54

Step 2: Add 30 to both sides.

6x − 30 + 30 = 54 + 30

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Step 3: Divide both sides by 6.

6x/6 = 84/6

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8 0
3 years ago
Rational numbers-oh my!
Anna [14]
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8 0
3 years ago
Which of the following represents 8 square root x5
gavmur [86]

Answer:

5 \sqrt{8}

6 0
3 years ago
A roofer leaned a 16-foot ladder against a house. If the base of the ladder is 5 feet from the house, how high up the house does
elixir [45]

Answer:

15.20feet

Step-by-step explanation:

Length of the ladder = 16foot (hypotenuse)

BAse of the ladder from the house = 5feet (adjacent)

height of the house = x (opposite)

Using the pythagoras theorem

hyp^2 = opp^2 + adj^2

16^2 = 5^2 + opp^2

256 = 25 + opp^2

opp^2 = 256-25

opp^2 = 231

opp =√231

opp = 15.20

Hence the house is 15.20feet high up the house

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2 years ago
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