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3 years ago

HELP ASAP - MATHS

Mathematics

2 answers:

Alinara [238K]3 years ago

8 0

F(x)=|x+2|
to move it 4 units to right, subtract 4 from every x
f(x)=|x-4+2|
f(x)=|x-2|

1st opton

allochka39001 [22]3 years ago

6 0

To translate 4 units to the right, you replace $x$ with $x-4$

So we get
$g(x)=|(x-4)+2|=|x-2|$

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Each student in a pottery class is responsible for cleaning the area around his or her workspace at the end of the lesson. Each

Kipish [7]

To find the total area cleaned, mult. 4 1/2 ft^2 by 13 (students):

9 ft^2

---------------- * 13 students = 58.5 ft^2

students

Second approach: Rewrite 4 1/2 as 4 + 1/2

and then mult. this result by 13:

13(4 + 1/2) = 52 + 13/2= 52 + 6.5 = 58 1/2 ft^2 (answer)

8 0

4 years ago

What is 613157 rounded to the nearest hundred thousand

lawyer [7]

Answer:

600,000

Step-by-step explanation:

Your answer would be 600,000 because in the hundred thousands place there is a 6.

And that 6 in the hundred thousands place is asking the ten thousands place for help also the digit in the ten thousands place is a 1.

So if you know the rule the 6 can't round up because the 1 is below 4./the rule is 4 and below keep it low 5 or more give it one more.

Ok so the 1 is below 4 and can't bring 6 up so 6 has to stay in it's lane at 600,000

Hope this helps have a great afternoon:)

5 0

3 years ago

Read 2 more answers

A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of

Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

Hours of TV per week (X): 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of hours of TV watched per week = $\frac{\sum X}{n}$ = 9.65

s = sample standard deviation = $\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }$ = 4.61

n = sample of people = 20

$\mu$ = true average number of hours of TV watched per week

Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 80% confidence interval for the true average, $\mu$ is ;

P(-1.33 < $t_1_9$ < 1.33) = 0.80 {As the critical value of t at 19 degrees of

freedom are -1.33 & 1.33 with P = 10%}

P(-1.33 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.33) = 0.80

P( $-1.33 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $9.65-1.33 \times {\frac{4.61}{\sqrt{20} } }$ , $9.65+1.33 \times {\frac{4.61}{\sqrt{20} } }$ ]

= [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0

3 years ago

How many solutions does this linear system have?

Naily [24]

B. y=2x-5
-4y=8x-20
y=-2x+5
2x-5=-2x+5
x=2.5
2x*2.5-5=0
-2x*2.5+5=0
so (2.5,0)

4 0

3 years ago

Read 2 more answers

I need help ASAP, please

Fantom [35]

Answer:

Step-by-step explanation:

7 0

2 years ago