Algebra 2... need help asap!
1 answer:
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Answer:
When kicked, the height of the ball is 1 feet. The highest point for the ball's trajectory is 12 feet.
Step-by-step explanation:
We are given that the height is given by . The distance between the ball to the point where it was kicked is 0 right at the moment the ball was kicked. So, the height of the ball, when it was kicked is f(0) = -0.11*0 + 2.2*0 +1 = 1.
To determine the highest point, we will proceed as follows. Given a parabola of the form x^2+bx + c, we can complete the square by adding and substracting the factor b^2/4. So, we get that
.
In this scenario, the highest/lowest points is
We will complete the square for . In this case b=-20, so
We can distribute -0.11 to the number -100, so we can take it out of the parenthesis, then
So, the highest point in the ball's trajectory is 12 feet.
So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x = 33.49° --> answer B) is correct
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x = 33.49° --> answer B) is correct