(3x - 8)(3x + 8) is 3.) 9x^2 - 64
(x + 6)^2 is 4.) x^2 + 12x + 36
(3x - 2)(x + 5) is 1.) 3x^2 + 13x - 10
5x(x - 1)(x + 7) is 2.) 5x^3 + 30x^2 - 35x
(x - 8)(x + 7) is 5.) x^2 - 10x + 16
I hope this helps!
Answer:
b) 9x² - 3x
Step-by-step explanation:
Area of a rectangle = Length × Width
Area for the rectangle = 3x - 1 × 3x
Area = 
Step 1. Multiply by combining like terms
3x · 3x = 9x²
Step 2. Multiply -1 by 3x
-1 · 3x = -3x
Step 3. Combine 9x² and -3x
9x² - 3x
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doomdabomb: All brainliest and thanks are appreciated
and would mean a lot to me, thanks!
Find the intersection of the following sets.<br><br>a= 1,2,3,4,5,6,7,8 b= 2,4,6,8,10<br>
Neporo4naja [7]
{2,4,6,8}
Intersection means common elements in both sets
Eighteen tens < 21 × (5+5)
Hope this helps!