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Assoli18 [71]
2 years ago
13

A triangle has vertices A(0, 0), B, (–2, 8), and C(1, 7). What are the coordinates of the triangle after a dilation with a scale

factor of 4?
Mathematics
2 answers:
Elina [12.6K]2 years ago
7 0

Answer:

Basically multiply the x and y coordinates of each point by 1/2

For example, I'll do C which is ( -2 , 10 )

-2 * 1/2 = -1 and 1/2 * 10 = 5

The new coordinate is ( -1 , 5 )

Now you can try the other points

ololo11 [35]2 years ago
5 0

Answer:

Step-by-step explanation:

mutiply x and y component by 4

A(0 , 0) = (4*0 ,,4*0)

A' = (0 , 0)

B(-2 , 8) = (-2*4 , 8*4)

B' = (-8 , 24)

C(1 , 7) = (1*4 , 4*7)

C' = (4 , 28)

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Solution to m^2- 36=0
alex41 [277]

Answer:

m=(-6,6)

Step-by-step explanation:

m^2 -36 = 0

Reorder the terms:

-36 + m^2 = 0

Solving for variable 'm'.

 Add '36' to each side of the equation.

-36 + 36 + m^2 = 0 + 36

Combine like terms: -36 + 36 = 0

0 + m^2 = 0 + 36

m^2 = 0 + 36

Combine like terms: 0 + 36 = 36

m^2 = 36

Simplifying

m^2 = 36

Take the square root of each side:

√m^2=+/-√36

m=(+/-)6

m = {-6, 6}

4 0
3 years ago
Given the parent function f(x) = 2^x, which graph shows f(x) + 1?
mixer [17]

Answer: First Option

a) exponential function going through point (0, 2) and ending up on the right

Step-by-step explanation:

Look at the attached image, the red line represents a function of the form:

f(x) = 2^x

Note that this function cuts to the axis and at the point (0, 1)

Also when x tends to ∞ f(x) tends to ∞ and when f(x) tends to -∞ then f(x) tends to zero.

If we perform the transformation y = f(x) +1 then the graph of y is equal to the graph of f(x) displaced 1 unit up. Then the new cutting point with the axis y will be: (0, 2) as shown in the attached image (blue line)

The transform function is y =2^x +1

Finally the answer is the first option

4 0
3 years ago
What is the length of RS.
Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0
3 years ago
The first term of a geometric sequence is 300 and the common ratio is 2 What is the 7th term of the sequence
xxMikexx [17]

Step-by-step explanation:

s1 = 300

s2 = s1 × 2 = 300 × 2 = 600

s3 = s2 × 2 = s1 × 2² = 1200

sn = sn-1 × 2 = s1 × 2^(n-1)

s7 = 300 × 2⁶ = 300 × 64 = 19,200

3 0
2 years ago
SOMEONE HELP ME PLEASE
IgorC [24]

A standard die has numbers = 1,2,3,4,5 and 6

Total outcomes = 6

P = Number of outcomes/Total Outcomes

Even and less than 4 = 1,2,3,4 and 6

P = 5/6

Answered by GauthMath if you like please click thanks and comment thanks

3 0
3 years ago
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