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Anon25 [30]
3 years ago
11

What is the solution to the following system

Mathematics
2 answers:
Travka [436]3 years ago
7 0

Answer:

C. Is you answer

Step-by-step explanation:

What you have to do is you take the second equation and plug it into the y of the first equation to get

-2x^2+-3x^2+5=-5. You will then add the -2x^2 and the -3x^2 together to get

-5x^2+5=-5. You will then minus the 5 from both sides to get

-5x^2=-10. You will then divide the -5 from both sides to get

x^2=2. You will then square root it to get

x=sqrt2 and -sqrt2.

You will then plug the sqrt2 into the second equation into the x like this

y=-3(sqrt2)^2+5. and you answer wil be -1.

So C is your answer.

Archy [21]3 years ago
3 0

C is the answer.............

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If x+3/3=y+2/3, then x/3= <br> A) y/3<br> B)y-1<br> C)y/2<br> D)y+1
Vlada [557]

Answer:

y/2

Step-by-step explanation:

x+3=y+2

------  --------

3          2

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2(x+3) = 3(y+2)

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2x+6 = 3y+6

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2x+6-6 = 3y+6-6

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3 years ago
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7 0
2 years ago
Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3). Find the coordinates of G.
Olin [163]

Answer:

Coordinates of G = (2,0)

Step-by-step explanation:

Given: Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3).

To find: coordinates of G

Solution:

Midpoints of a side joining points (a,b),\,(c,d) are given by (\frac{a+c}{2},\frac{b+d}{2})

Diagonals of a parallelogram bisect each other.

So,

Midpoint of DF = Midpoint of EG

Midpoint of DF = (\frac{-4+3}{2},\frac{-2+3}{2})=(\frac{-1}{2},\frac{1}{2})

Midpoint of EG = (\frac{-3+x}{2},\frac{1+y}{2})

Let coordinates of G be (x,y)

Therefore,

(\frac{-1}{2},\frac{1}{2})  =(\frac{-3+x}{2},\frac{1+y}{2})\\\\\frac{-1}{2}=\frac{-3+x}{2},\,\frac{1}{2}=\frac{1+y}{2}\\\\-1=-3+x,\,1=1+y\\\\x=-1+3,\,y=1-1\\x=2,\,y=0

So,

Coordinates of G = (2,0)

8 0
2 years ago
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