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prohojiy [21]
3 years ago
5

What is the slope of a line perpendicular to the line whose equation is x-y=6

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Answer:

1

hope this helps!!:)

Step-by-step explanation:

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Answer:

Y = 15sqrt(3)/4

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Step-by-step explanation:

Sin(60) =Z/15

sqrt(3)/2 = Z/15

Z = 15sqrt(3)/2

Sin(30) = Y/Z

½ = Y/Z

Y = ½(15sqrt(3))/2 = 15sqrt(3)/4

Cos(30) = b/Z

sqrt(3)/2 = b/Z

b = 15sqrt(3)/2 × sqrt(3)/2

b = 45/4

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Step-by-step explanation:

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