Two objects are moving along separate linear paths where each path is described by postion, d, and time, t. The variable d is me
asured in meters and the variable t is measured in seconds. The equation describing the graph of the postion of the first object with respect to time is d=2.5t+2.2. The graph of the the position of the second object is a parallel line passing through (t=0,d=1). What is the equation of the second graph. d=2.5t+1
d=-0.4t+1
d=2.5t+3.2
The first equation is: d = 2.5 t + 2.2 For the parallel line : m = 2.5. It is passing through: t = 0, d = 1 d = m t + b 1 = 2.5 * 0 + b b = 1 Answer: A ) d = 2.5 t + 1
BC and BCE are Before Common Era So what you want to do is add 1952 and 384 1952 + 384 = 2336 So the amount of years between 384 BC and 1952 AD is about 2,336 years Hope this helps
Shift the decimals of both 213480 and 59.3 to the right by 2 decimal places. (This is needed to convert 59.3 to 5930, since long division must divide by a whole number.)
