What is the answer to a+5= -5a+5

Use multiplication and the distributive property to find the quotient 96/6

SashulF [63]

The answer to your problem will be 16

6 0

3 years ago

Wwwwwwwwwwwwwwwwwwwww

nordsb [41]

Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

4 0

3 years ago

The volume of a pyramid that fits exactly inside a cube is 18 cubic feet. what is the volume of the cube? 6 cubic feet 18 cubic

fomenos

The volume of the cube that perfectly fits an 18 ft³ pyramid is calculated as (C) 54 ft³.

A cube is a three-dimensional solid object with six square faces, facets, or sides, three of which meet at each vertex.
The cube is one of the five Platonic solids and the only regular hexahedron.
It has six faces, twelve edges, and eight vertices.

To find the volume of the cube that perfectly fits an 18 ft³ pyramid:

We have been provided that:

18 cubic feet is the volume of the pyramid.
Now, in order for this pyramid to fit exactly into a cube, the base of the pyramid must be square, and the height of the pyramid must be equal to the height of the cube.
We can conclude from this that the volume of a cube equals three times the volume of a pyramid.
So, the volume of the cube = 3 × 18
The volume of Cube = 54 ft³

Therefore, the volume of the cube that perfectly fits an 18 ft³ pyramid is calculated as (C) 54 ft³.

Know more about a cube here:

brainly.com/question/1972490

#SPJ4

The correct question is given below:

The volume of a pyramid that fits exactly inside a cube is 18 cubic feet. what is the volume of the cube?

(A) 6 cubic feet

(B) 18 cubic feet

(C) 54 cubic feet

(D) 72 cubic feet

6 0

9 months ago

Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

3 0

2 years ago

Althea and her sister want to hang 5 pics on a 12-foot wall. Each pic frame must be equal distance apart from each other and the

omeli [17]

the answer to it is the frames has to be 94 ithink

8 0

3 years ago

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