Which of the following is a composite number? A 1 B 0 C 63 D 19

2 answers:

5 0

Composite numbers are numbers with factors.

63 = 7 x 9
There 7 and 9 are 2 possible factors of 63
Therefore 63 is a composite number

vfiekz [6]3 years ago

4 0

19 is the composite number

You might be interested in

Only using 1 2 3 4, find a solution that equals 18, 19, 20, and 21

adoni [48]

Answer:

See below, there may be more than one answer

Step-by-step explanation:

4(3+1)+2 = 18

(4+2)(3)+1 = 19

(1)(2+3)(4) = 20

(1+2)(3+4) = 21

6 0

3 years ago

What two numbers product is 72 and sum is 17

iVinArrow [24]

That would be 8 and 9.

9*8=72
While 9+8=17

I hope this helps! (:

8 0

4 years ago

Read 2 more answers

HELP THIS WAS DUE ALREADY

sergeinik [125]

Answer:

1:4

Step-by-step explanation:

Let's find the ratio of one side of Figure A to one side of Figure B. Note that the have to be the same side on each triangle (Ex: The short side and the short side or the medium length side and the medium length side or the long side and the long side)...

14:56

We can simplify this into...

1:4

4 0

2 years ago

Read 2 more answers

1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg

tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

$d=\sqrt{x^2+y^2}$

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

$\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}$