Answer:
(300-200)=100Divided by 5
Step-by-step explanation:
The first term is a₁ = 2.
Each subsequent term is the reciprocal of the square of the preceding term.
2nd term:
a₂ = 1/2² = 1/4
3rd term:
a₃ = 1/(1/4)² = 1/(1/16) = 16
4th term:
a₄ = 1/16² = 1/256
5th term:
a₅ = 1/(1/256)² = 1/(1/65536) = 65536
The positive square root of the fifth term is
√(65536) = 256
Answer: 256
89,170,326
millions is the place value of 9
hope that helps :)
You only have to apply the theorem of Pythagoras here. Remember the square on the hypotenuse (the longest side) is equal to the sum of the squares on the other two sides :
1. AB is the hypotenuse, so, according to the theorem we can write :
AB² = AC² + CB²
c² = 5² + 4²
c²= 25 + 16
c² = 41
applying the square root of 41 we get :
c ≈ 6.40 rounded to the hundred
The next cases are exactly the same thing so there is no need for explanation :
2.
AB is the hypotenuse here because it is the biggest side clearl :
AB² = AC² + CB²
25² = 15² + b²
Thus
b² = 25² - 15²
we just subtracted 15² on each side of the equation
b² = 625 - 225
b² = 400
applying the square root of 400 we get
b = √400 = 20
So AC = 20
3. The longest side is clearly AB = 60
So
AB² = AC² + CB²
60² = 40² + a²
subtracting 40² on each side of the equation we get :
a² = 60² - 40²
I let you finish this using your calculator and doing exactly like the previous cases
4.
AB is the hypotenuse,
AB² = AC² + CB²
23² = b² + 14²
Subtracting 14² from each side of the equation we get
b² = 23² - 14²
5.
AB is the biggest side :
AB² = AC² + CB²
29² = 23² + a²
We subtract 23² on each sides of the equation :
a² = 29² - 23²
You can finish with your calculator
6.
AB² = AC² + BC²
78² = b² + 30²
subtraction...
b² = 78² - 30²
Good luck :)
Answer:
a) Hence, the probability of this event occurring if, in fact, the DOT's claim is true
= 3/10 = 0.3
Step-by-step explanation:
a) The concept applied here is combinatorics ; nCr = n!/(n - r)!r!
we are told that out of 5bidders, Three of the bidders were large construction conglomerates
and two were small specialty contractors.
selecting two recipients with tree of the bidders were large construction conglomerates 3C2
= 3!/(3-2)!2!
= 3
Similarly, selecting the two small casualty contractor from the total of 5bidders = 5C2
= 5!/(5-2)!2!
= 10
Hence, the probability of this event occurring if, in fact, the DOT's claim is true
= 3/10 = 0.3
b) if DOTs claim is not true ( probability of failure) = 1 - 0.3
= 0.7 , this value implies that the probability 0.3 is largely compatible and a compliment of the 0.7 and as such it is consistent with the DOTs claim that the selection was random.
