Answer:
50
Step-by-step explanation:
If the first statement its true (At most 0 of the statements are true), there are not true statements in the paper. So, the first statement its false.
Now, if the first statement its false, this mean there must be at least 1 true statement in the paper.
Now, if the second statement its true ( at most 1 of the statements are true) this implies that the third statement its true (if "at most 1" its true, then "as most 2" must be true).
If any statement (besides the first) its true, then all the statement that follows it must be true.
The first non false statement, then, must be the statement made by the person 51: "At most 50 statements are true"
And the 49 statements that follows are true as well.
Is this a system of equations? Lmk in the comments
Can you at least shows the numbers?
Answer:
x=1.5
Step-by-step explanation:
We are trying to get x by itself to see what it equals.
6(2x+3)=36
So first you want to distribute you proprieties. You do that by multiplying 6 and 2x. Then multiplying 6 and 3.
12x+18=36
Now in equations where you need to find the variable, whatever you do on one side of the equal sign, you have to do on the other side. So now we want to subtract 18 from both sides.
12x+18=36
-18 -18
Then we divide 12 from both sides.
12x=18
÷12 ÷12
Now you have your answer!
x=1.5
The required system of inequalities is:
-2x + 3y > 15
y + 3x ≥ -4
y + 11x ≥ 6
In the given graph:
The dotted line represents the equation:
-2x + 3y = 15 → line 1.
The line towards the left of the shaded region represents the equation:
y + 3x = -4 → line 2.
The line towards the right of the shaded region represents the equation:
y + 11x = 6 → line 3.
Let's take a point in the shaded region and use the equations of the line to determine the inequality.
Consider the point (-2, 6) and substitute these values in the equations of all three lines.
Line 1:
LHS of line 1 = -2x + 3y = -2(-2) + 3(6) = 4 + 18 = 22
RHS of line 2 = 15.
Therefore, LHS > RHS.
⇒The required inequality is -2x + 3y > 15. It is a strict inequality since the equation of the line is not included in the shaded region.
Line 2:
LHS of line 2 = y + 3x = 6 +3(-2) = 6 - 6 = 0
RHS of line 2 = -4
Therefore, LHS > RHS.
⇒The required inequality is y + 3x ≥ -4. The "Equal to" symbol is used because the equation of the line is included in the shaded region.
Line 3:
LHS of line 3 = y + 11x = 6 + 11(-2) = 6 - 22 = -16
RHS of line 3 = 6
Therefore, LHS < RHS.
⇒The required inequality is y + 11x ≥ 6. The "Equal to" symbol is used because the equation of the line is included in the shaded region.
Therefore, the required system of inequalities is:
-2x + 3y > 15
y + 3x ≥ -4
y + 11x ≥ 6
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