Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
9*2 =18 add 27 =45 this is the answer hope this helped
Answer:
100
Step-by-step explanation:
Write in an equation:
4=4%x, then divide 4% from both sides, and then you get 100.
Answer:
t = 0.77930
t = 1.2832
Step-by-step explanation:
