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snow_lady [41]
3 years ago
14

Find the quadratic function that has the vertex (4,5) and passes through the point (8,21) If possible, can you explain the work?

Thanks! *71 POINTS!*

Mathematics
1 answer:
Ganezh [65]3 years ago
8 0
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!

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5 0
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I need help ASAP I will give brainliest if correct
alexdok [17]
Part 1)
we know that
the property of cyclic quadrilaterals for which opposite angles are supplementary
then
m∠A°+43°=180°------------> m∠A=180°-43°=137°

the answer is m∠A=137°


Part 2) 
<span>Quadrilateral ABCD ​ is inscribed in a circle. What is the measure of angle A?

we know that
</span>the property of cyclic quadrilaterals<span> for which opposite angles are supplementary
then:</span>
<span>m∠A+m∠C=<span>180<span>∘
(2x+9)+(3x+1)=180---------------> 5x+10=180
x=(180-10)/5=34

</span></span></span>m∠A=2x+9-------------> 2*34+9=77°
<span>
the answer is </span>m∠A=77°<span>

</span>
8 0
4 years ago
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