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snow_lady [41]
3 years ago
14

Find the quadratic function that has the vertex (4,5) and passes through the point (8,21) If possible, can you explain the work?

Thanks! *71 POINTS!*

Mathematics
1 answer:
Ganezh [65]3 years ago
8 0
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!

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zaharov [31]

(x - 5) is a factor of the polynomial function f(x) = x³ - x² - 17x -15 as there is no remaider.

<h3>What is a factor of a polynomial?</h3>

We know that if x = a is one of the roots of a given polynomial x - a = 0 is a factor of the given polynomial.

To confirm if x - a = 0 is a factor of a polynomial we replace f(x) with f(a) and if the remainder is zero then it is confirmed that x - a = 0 is a factor.

Given a polynomial function f(x) = x³ - x² - 17x -15.

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learn more about factor of a polynomial here :

brainly.com/question/26354419

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