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Lemur [1.5K]
4 years ago
11

How do you solve the problem -x-29=13+2x

Mathematics
1 answer:
serious [3.7K]4 years ago
7 0
-x-29=13+2x
-29=13+3x
-42=3x
x=-14
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Give the appropriate theorem or postulate that can
Ratling [72]

Answer:

Step-by-step explanation:

<ACB = <ECD    

These 2 angles are vertically opposite and are equal.

<B = <D

They are both right angles are therefore equal.

The answer is the AA postulate.

A

Note

ASA is a congruence postualate. If S is between two angles that can be shown to be corresponding and equal, then you will have 2 congruent triangles.

SSS if three sides of 1 triangle = 3 sides of a second triangle, then the 2 triangles are congruent. If the the three sides of one triangle are in a ratio with 3 sides of the other triangle, then the triangles could be similar, but that is not the case here.

SAS this is the terminology for congruence as well. We don't know enough to use it for similarity. Some sort of ratio would have to be mentioned to do that.

You are intended to use AA as your answer.

8 0
2 years ago
Ryan has 3.25 pounds of hamburger. How many 0.25 pound hamburgers can he make?
Marina86 [1]
Ryan has 3.25 of hamburger. How many 0.25 pound of hamburgers can he make? The answer: 13
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What is the slope of a line parallel to line Y= 3x +2
masya89 [10]

It is already Parraell.

5 0
3 years ago
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HELPPPP <br><br> When y=4x-6 find y if x=1/2
Gnom [1K]

Answer: y = -4

Step-by-step explanation:

y = 4x-6

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3 years ago
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Please help and thank you
tatiyna

Answer:

b_{1}=\frac{2A}{h}-b_{2}

Step-by-step explanation:

Given: A=\frac{1}{2}(b_{1} +b_{2})h

We need to completely isolate b_{1} to solve.

A=\frac{1}{2}(b_{1} +b_{2})h

A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h

A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}

Finally, multiply both sides by -2 to completely isolate b_{1}.

b_{1}=\frac{2A}{h}-b_{2}

5 0
3 years ago
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