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krok68 [10]
3 years ago
13

I NEED HELP ASAP ...

Mathematics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

13%

Step-by-step explanation:

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Here is an image that might help you understand placements.

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Answer:

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Step-by-step explanation:

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A variable force of magnitude F(x) moves a body of mass m along the x-axis from x1 to x2. The net work done by the force in movi
kicyunya [14]

Answer:

w=\frac{1}{2}m(v^2_2-v^2_1)

Step-by-step explanation:

We are given that a variable force of magnitude F(x) moves a body along the x- axis from x_1 to x_2.

The net work done by the force in moving the body from x_1 to x_2 .

v_1=Velocity of the body at x_1

v_2=Velocity of the body at x_2

We know that

Work done=Final kinetic energy-Initial kinetic energy

w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1

K.E=\frac{1}{2}mv^2

Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)

Hence, the net work done by the force is given by

w=\frac{1}{2}m(v^2_2-v^2_1)

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3 years ago
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Fiesta28 [93]
False, bc when you plug in the x and y values the equation isnt true.
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2 years ago
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