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lora16 [44]
3 years ago
15

Simplify the square root of x to the power of 16 times y to the power of 36.

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

\large\boxed{x^8y^{18}}

Step-by-step explanation:

\sqrt{x^{16}\times y^{36}}\\\\\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{x^{16}}\times \sqrt{y^{36}}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\=\sqrt{x^{8\cdot2}}\times\sqrt{y^{18\cdot2}}=\sqrt{(x^8)^2}\times\sqrt{(y^{18})^2}\\\\\text{Use}\ \sqrt{a^2}=|a|\\\\=|x^8|\times|y^{18}|\\\\\text{Because}\ x^8\geq0\ \text{and}\ y^{18}\geq0\ \text{for any value of x and y we have}\\\\=x^8\times y^{18}=x^8y^{18}

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X*2 +5 =41
Subtract 5 from both sides
X*2=36

Square root of 36 is 6

X=6

Solve

6*2+5 =41
This’s correct!
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Answer:

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Step-by-step explanation:

First find the midpoint of the diameter, because that represents the center of the circle.

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Use the Pythagorean Theorem to determine the square of the radius:

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Answer:

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Step-by-ste:

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