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Valentin [98]
3 years ago
10

Solve the equation using square roots. x2 + 5 = 41

Mathematics
2 answers:
Stells [14]3 years ago
3 0
X*2 +5 =41
Subtract 5 from both sides
X*2=36

Square root of 36 is 6

X=6

Solve

6*2+5 =41
This’s correct!
Kipish [7]3 years ago
3 0

Answer:  The required solution is x = 6,  -6.

Step-by-step explanation:  We are given to solve the following quadratic equation using square roots :

x^2+5=41~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To solve a quadratic equation by square root method, we need to take x² term on one side and the constant term on the other. After that, the square root on both the sides are taken.

From equation (i), we have

x^2+5=41\\\\\Rightarrow x^2=41-5\\\\ \Rightarrow x^2=36\\\\\Rightarrow x=\pm\sqrt{36}~~~~~~~~~~~~\textup{[taking square root on both the sides]}\\\\\Rightarrow x=\pm 6.

Thus, the required solution is x = 6,  -6.

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<img src="https://tex.z-dn.net/?f=%2826%20%5Cdiv%20100%29%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5Ctimes%2010" id
taurus [48]

Answer:

\boxed{\bf \:  \cfrac{13}{5}}

<u>Or in Decimal:</u>

\boxed{\bf \: 2.6}

Step-by-step explanation:

<u>Given expression :-</u>

\sf \: ( 26 \div 100) \times 10

<u>Solution :-</u>

\sf  = (26 \div 100 )\times 10

This arithmetic expression may be rewritten as ;

\sf  =  \cfrac{26}{100}  \times 10

Step 1 : <u>Cancel the zero of 10 and one zero of 100</u> :-

\sf  =  \cfrac{26}{10 \cancel0}  \times 1 \cancel0

<em>Results to;</em>

\sf  =  \:  \cfrac{26}{10}  \times 1

\sf  =  \:  \cfrac{26}{10}

Step 2: <u>Cancel 26 and 10</u><u> </u><u>by 2</u> :-

\sf  =  \cfrac{ \cancel{26}}{ \cancel{10}}

<em>Results to;</em>

\sf = \cfrac{ \cancel{26} {}^{13} }{ \cancel{10} {}^{5} }

\sf  =  \cfrac{13}{5}

<em>It can also be in Decimal.</em>

That is;

\sf = 2.6

Hence, the answer of the expression would be 13/5 or 2.6 .

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

I am joyous to help!

3 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!! WORTH 10 POINTS!!!
Sidana [21]
<span>slope
m = (1  - 1)/(0 + 2) = 0

(x1, y1) as (-2, 1)

</span><span>point-slope form</span><span>
y - y1 = m(x - x1)
y - 1 = 0(x + 2)
y - 1 = 0
y = 1</span>
7 0
3 years ago
A rug is shaped like a parallelogram with a base of 41⁄2 ft. and a height of 2 1⁄4 ft. What is the area of the rug? Draw and lab
Bess [88]

Answer:

46.125 square feet or 46\dfrac{1}{8} sq. feet.

Step-by-step explanation:

The rug is shaped like a parallelogram with a base of \frac{41}{2} = 20.5 feet. and a height of 2\dfrac{1}{4} = 2.25 feet.

Now, the area of a parallelogram is given by the product of one side as the base and the perpendicular distance of that side from the opposite parallel side as height.

Now, the area of the given parallelogram is (20.5 × 2.25) = 46.125 square feet. (Answer)

7 0
4 years ago
Y^2 +5y+4= ???????????????
joja [24]

Answer:

y²+5y+4=y²+4y+y+4=y(y+4)+1(y+4)=

<u>(y+4)(y+1)</u>

4 0
3 years ago
Parse the regular hexagon, and tell how much regular unit triangle do you find, if the length of one side of the regular hexagon
Thepotemich [5.8K]

Answer:

Six.

Step-by-step explanation:

In geometry, a hexagon is a two-dimensional polygon that has six sides. A regular hexagon is a hexagon in which all of its sides have equal length. We sometimes define a regular hexagon using equilateral triangles, or triangles in which all of the sides have equal length.

The regular hexagon is a convex polygon with six equal sides and six equal angles. Each external angle of the regular hexagon measures 60 degrees. It is closely related to equilateral triangles: Joining each vertex with its opposite, the regular hexagon is divided into six equilateral triangles.

5 0
3 years ago
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