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Valentin [98]
3 years ago
10

Solve the equation using square roots. x2 + 5 = 41

Mathematics
2 answers:
Stells [14]3 years ago
3 0
X*2 +5 =41
Subtract 5 from both sides
X*2=36

Square root of 36 is 6

X=6

Solve

6*2+5 =41
This’s correct!
Kipish [7]3 years ago
3 0

Answer:  The required solution is x = 6,  -6.

Step-by-step explanation:  We are given to solve the following quadratic equation using square roots :

x^2+5=41~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To solve a quadratic equation by square root method, we need to take x² term on one side and the constant term on the other. After that, the square root on both the sides are taken.

From equation (i), we have

x^2+5=41\\\\\Rightarrow x^2=41-5\\\\ \Rightarrow x^2=36\\\\\Rightarrow x=\pm\sqrt{36}~~~~~~~~~~~~\textup{[taking square root on both the sides]}\\\\\Rightarrow x=\pm 6.

Thus, the required solution is x = 6,  -6.

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\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
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<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

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<u>Here</u><u>, </u>

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Thus, The common difference is 12

<u>Now</u><u>, </u>

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\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

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