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3 years ago

(h(1) = 14 h(n) 28 hin - 1) h(2) =

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

Y=ax2

Step-by-ste:

Y=ax28(n)

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3. In a lake, there is a patch of lily pads. Every day, the patch doubles in size. If it takes 48 days for the patch to cover th

SSSSS [86.1K]

The patch doubles in size each day so, on the 47th will be half the size than on the 48th day

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3 years ago

An experiment consists of rolling a die, flipping a coin, and spinning a spinner divided into 7 equal regions. The number of ele

oee [108]

Answer:

Option A.

<em>The number of elements in the sample space of this experiment is 84</em>

Step-by-step explanation:

The sample space for an experiment represents the number of possible results that may occur when conducting the experiment.

When throwing a die and observe the number obtained there are 6 possible results

When throwing a coin there are 2 possible results.

When spinning a wheel divided into 7 regions we have 7 possible outcomes.

If we combine these three experiments, then the sample space S is composed of the product of the possible results of each experiment.

$S = (6)(2)(7)\\\\S =84$

5 0

3 years ago

Help me fast ASAP pls

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

I got it right

5 0

3 years ago

Three to the third power +6 (2+3/6)

BigorU [14]

3x3x3 which is 18 :)))

3 0

3 years ago

A survey conducted by a leading HMO found that of 2000 women, 340 were heavy smokers and 25 had emphysema. Of those who had emph

belka [17]

Answer:

The events being a heavy smoker and having emphysema are not independent.

Step-by-step explanation:

We are given the following in the question:

Number of women = 2000

Number of heavy smoker = 340

Number of women who has emphysema = 25

Number of women who has emphysema and are heavy smoker = 21

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

P(Smoker) =

$P(S) = \dfrac{340}{2000}=0.17$

P(emphysema) =

$P(E) = \dfrac{25}{2000}= 0.0125$

P(Smoker and emphysema) =

$P(S\cap E) = \dfrac{21}{2000} = 0.0105$

Two events A and B are said to be independent if

$P(A\cap B)=P(A)\times P(B)$

Checking conditions for independence:

$P(S)\times P(E) = 0.17\times 0.0125=0.002125\\P(S)\times P(E) \neq 0.0105\\P(S)\times P(E)\neq P(S\cap E)$

Thus, the events being a heavy smoker and having emphysema are not independent.

3 0

3 years ago