Answer:
The answer is below
Step-by-step explanation:
Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:
y = (1/2)x (1)
Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:
200/x + 200/y = 4 (2)
Put y = (1/2)x in equation:

Put x = 150 in equation y:
y=(1/2)150 = 75
Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour
Answer:
See below
Step-by-step explanation:
IN a right triangle , remember S-O-H-C-A-H-T-O-A <===memorize this!
sin z = O/H = opposite side/hypotenuse = 16/20
cos z = A/H = adjacent / hy[potenuse = 12/20
tan z = O/A = 16/12
The unknown number would be 11
738 + 164 = 902
902 / 82 = 11
Ans: 11