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suter [353]
3 years ago
11

"how many ways are there to construct a string of 3 digits if numbers cannot be repeated

Mathematics
2 answers:
solniwko [45]3 years ago
8 0
There are 10 total digits ( 0, 1 , 2, 3, 4, 5, 6, 7,8 ,9)

1st digit can be 1 of 10
2nd digit can be 1 of 9 ( 10-1 because a number cannot repeat)
3rd digit can be 1 of 8 ( 9-1 because no number can repeat)

total combinations = 10 * 9 * 8 = 720
Vladimir [108]3 years ago
7 0

\underbrace{10}_{\text{1 of 10 digits}}\cdot \underbrace{9}_{\text{1 of remaining 9 digits}}\cdot \underbrace{8}_{\text{1 of remaining 8 digits}}=720

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Correct response:

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<h3>Methods of calculation using a histogram</h3>

The estimate of the number of students who revised for less than 45

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Learn more about histograms here:

brainly.com/question/17139138

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