Answer:
c. 7 candies and 9 nuts
Step-by-step explanation:
c.. 7 and 9
The answer of your question is 8.333 yards
What types of problems can be solved using the greatest common factor? What types of problems can be solved using the least common multiple? Complete the explanation.
<span>*** Use the words 'same' and 'different' to complete the following sentences.*** </span>
<span>Problems in which two different amounts must be split into (the same) number of groups can be solved using the GCF. Problems with events that occur on (different) schedules can be solved using the LCM.</span>
Answer:
0.8914
Step-by-step explanation:
You want to find the z-values associated with the x-values:
z = (x -μ)/σ
z1 = (57 -90)/12 = -2.75
z2 = (105 -90)/12 = 1.25
Look up these values in a probability table and find the difference of the table values.
p(z < z1) ≈ 0.00298 . . . . from a table or calculator
p(z < z2) ≈ 0.89435 . . . . from a table or calculator
p(57 < x < 105) ≈ 0.89435 -0.00298 = 0.89137 ≈ 0.8914
An object that is in motion as a projectile follows a path or trajectory of a parabola
The function and values are;
- a) The equation of the quadratic function is;

- b) The maximum height of the ball is approximately <u>7.334 m</u>
- c) Horizontal distance at maximum height <u>18.8 meters</u>
<u />
Reason:
a) Known parameters are;
Let f(x) = a·x² + b·x + c represent the equation of the parabola modelling the path of the ball, we have;
Points on the path of the parabola = (0, 0), (35, 1.5), 37, 0)
Plugging the values gives;
0 = a·0² + b·0 + c
Therefore, c = 0
1.5 = 35²·a + 35·b
0 = 37²·a + 37·b
Solving gives;
a = -3/140, b = 111/140
The equation of the quadratic function is therefore;
b) The maximum height is given by the vertex of the parabola
The x-coordinate at the vertex is the point 
Which gives;

The maximum height is therefore;

The maximum height of the ball is approximately 7.334 m
c) The distance the ball has travelled to horizontally is given by half of the range, <em>R</em> as follows;
The range of the motion, R = 37 meters

Therefore;

The distance the ball has travelled horizontally to reach the maximum height horizontally <u>18.5 meters</u>
Learn more about the trajectory of a projectile here:
brainly.com/question/13646224