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3 years ago

Heeeelp me plz i will give brainliest

Mathematics

2 answers:

Neko [114]3 years ago

8 0

I think primary consumer because it does not work as a decomposer either a producer.

katen-ka-za [31]3 years ago

3 0

Most of the time, plants are producers because they get their food from photosynthesis. Lily pads do, so it is a producer.

Hope this helps!

You might be interested in

Last week Elle bought 4 apples for $2.40. This week she bought 9 apples for $5.40. If the cost per apple remains the same, how m

OlgaM077 [116]

Answer:

4 apples are $2.40

That means that 2 apples will be $1.20

And that one apple will be $0.60

$0.60*9= $5.40

She buys 5 more apples each week so she will buy 14 apples this week

$0.60*14= $8.40

Final answer : She will buy 14 apples next week for $8.40

Hope it helped! : )

8 0

3 years ago

Paul was thinking of a number. Paul adds 10, then divides by 2 to get an answer of -13. What was the original number?

frozen [14]

Answer:

I believe its -36

Step-by-step explanation:

-36+10=-26

-26/2= -13

3 0

3 years ago

Read 2 more answers

Expand then simplify: 12(2p-3)

avanturin [10]

Answer:

expanding ends in the simplest form: 24p-36

Step-by-step explanation:

7 0

4 years ago

Use a diagram words, and angle relationships to explain your answer

tankabanditka [31]

Answer:

네, 죄송합니다. 알았어 알았어. 알았어. 그러면 너는 내 대답을 위해 이것을하고있다.

8 0

3 years ago

Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are

o-na [289]

Answer:

x=-7

y=11

Step-by-step explanation:

Perpendicular Vectors

Two vectors defined as their endpoints $\vec u=$ and $\vec v=$ are perpendicular if their dot product a.b is zero. The dot product is

$\vec u.\vec v=ac+bd$

In other words

ac+bd=0

Let's treat all the points as the extremes of vectors, so we can easily find the missing coordinates

B (3,5) and C (7,15) define a segment, the vector

$\overrightarrow{BC}==$

The point A is A (x,9), we need to form a vector with B

$\overrightarrow{AB}==$

this vector must be perpendicular to BC, so, applying the dot product we have

$4(x-3)+40=0$

$4x-12=-40$

$x=-7$

The point D is D(17,y), we need to form a vector with C

$\overrightarrow{CD}==$

this vector must be perpendicular to BC, so, applying the dot product we have

$(4)(10)+(10)(y-15)=0$

$40+10y-150=0$

$10y=110$

$y=11$

The points are

$\boxed{A(-7,9), D(17,11)}$

4 0

3 years ago