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Tasya [4]
3 years ago
5

write the equation of a line that is perpendicular to the given line and that passes through the given point. y-4=5/2(x+3) ; (-7

,8)
Mathematics
2 answers:
faltersainse [42]3 years ago
7 0
The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.

The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.
Jobisdone [24]3 years ago
4 0
Comparing equation y-4 = 5/2(x+3) with slope-point form y-y1=m(x-x1), slope of given line is 5/2. Let m' be the slope of required line. product of the slope of perpendicular lines is equal to -1. Therefore, mxm' = -1. m' = -2/5. Using slope-point form to find the equation of required line, y-y1 = m(x-x1) . y-8 = -2/5(x-(-7)). y-8 = -2/5(x+7).
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Answer:

15.8m

Step-by-step explanation:

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liubo4ka [24]

\frac{ - 3}{10}

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6 0
2 years ago
f(x)=(2x−1)(3x+5)(x+1) has zeros at x= -5/3, x= -1 and x= 1/2 What is the sign of f on the interval -5/3
Crazy boy [7]

The sign of f on the interval -5/3 is negative

<h3>How to determine the sign?</h3>

The function is given as:

f(x)=(2x−1)(3x+5)(x+1)

The zeros of the function are

x= -5/3, x= -1 and x= 1/2

Next, we plot the graph of the function

At x = -5/3, the function approaches negative infinity

This means that the sign of f on the interval -5/3 is negative

Read more about function intervals at:

brainly.com/question/27831985

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6 0
2 years ago
Solve for angel GLN<br><br> please help asap, need help
likoan [24]

Answer:

119

Step-by-step explanation:

\mathrm{Supplementary\:angles\:add\:up\:to}\:180^{\circ }

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6 0
3 years ago
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