Reaction of combustion of butane is a as follows:
2 C₄H₁₀ + 13 O₂ --> 8 CO₂ + 10 H₂O:
As it can be seen from the equation that 2 mole of butane produce= 8 mole of butane produce
1 mole of butane produce= 4 mole of butane produce
1.60 g of butane=
= 0.027 mole of butane
0.027 mole of butane =
= 0.108 mole of CO₂.
Using ideal gas equation,
Here,
P denotes pressure
V denotes volume
n denotes number of moles of gas
R denotes gas constant
T denotes temperature
The values at STP will be:
P=1 atm
T=23+273 K = 296 K
R=0.0821 atm L mol ⁻¹
Number of moles of gas, n= 0.018
Putting all the values in the above equation,
V= 2.62 L
So the volume will be 2.62 L
The conversion factor for volume at STP is
or \frac {22.4L}{1mol}. Since we want volume, we would use \frac {22.4L}{1mol}. We conclude with the following calculations:
The answer is 44.8L Cl2
Answer:
HS+Na=>NaS+1/2H2(here HS- acts as an acid)
HS-. + HCl=> H2S(g)+ Cl-(here HS- acts as a base)
Clastic rocks are classified by grain shape, grain size, and sorting. Chemical sedimentary rocks are precipitated from water saturated with dissolved minerals. Chemical rocks are classified mainly by the composition of minerals in the rock.
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Answer: Option C) 0.64kPa
Explanation:
Given that,
Original volume V1 = 11.2 L
original pressure P1 = 0.860kPa
New volume V2 = 15.0 L
New pressure P2 = ?
Since pressure and volume are involved while temperature is constant, apply Boyle's law
P1V1 = P2V2
0.860 kPa x 11.2 L = P2 x 15.0L
9.632 kPaL = P2 x 15.0L
P2 = 9.632 kPaL / 15.0L
P2 = 0.64 kPa
Thus, the pressure of the gas is 0.64kPa