Answer:
The partial pressure of oyxgen O2 is 606 mmHg
Explanation:
Step 1: Data given
Percentage N2 = 22.8 %
The total pressure = 785.0 mmHg
Step 2: Calculate partial pressures
Partial pressure = percentage * total pressure
Partial pressure N2 = 0.228 * 785.0 mmHg
Partial pressure N2 = 179 mmHg
Step 3: Calculate partial pressure O2
Partial pressure O2 = 785.0 mmHg - 179.0 mmHg
Partial pressure O2 = 606 mmHg
OR (1 - 0.228) * 785.0 = 606 mmHg
The partial pressure of oyxgen O2 is 606 mmHg
Animals, plants, Humans
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Answer:
d = 2.5 g/L
Explanation:
Given data:
Molar mass of gas = 56 g/mol
Density of gas = ?
Temperature = 273.15 K
Pressure = 1 atm
Solution:
Formula:
d = PM/RT
d = 1 atm × 56 g/mol / 0.0821 atm.L/mol.K ×273.15 K
d = 56 atm g/mol./ 22.42 atm.L/mol
d = 2.5 g/L
A decrease in electronegativity happens when you go down group 17. This is due to the fact that as you go down the group, the atomic radius goes up which means <span>the first ionization energy decreases since shielding goes up.</span> All of those facts above shows that as you go down the group the atom looses the ability to draw electrons to itself which means that the electronegativity is going down the further down the group you go.
I hope this helps. Let me know in the comments if anything is unclear or if you want me to add any further explanation.