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Sergeu [11.5K]
3 years ago
6

How many grams of C3H8 would be needed to produce 6.39 grams of CO2?

Chemistry
1 answer:
just olya [345]3 years ago
8 0

Answer:

2.13g

Explanation:

Atomic mass of CO2 =  12 + 32 = 44g/Mol

Atomic mass of C3H8 = 36 + 8 = 44g/Mol

Reaction

C3H8 + 5O2 --> 3CO2 + 4H2O

3CO2 = 6.39g

Required C3H8 = (6.39/(44 x 3)) x 44 = 2.13g  

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What will litmus paper turn when it reacts with sodium nitrate?​
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3 years ago
Chloroform flows through a 4.26 inch inside-diameter pipe at the rate of 3.60 gallons per minute. What is the average velocity o
Pani-rosa [81]

Answer:

1) 0,081 ft/s

2) 0,746 lb/s

Explanation:

The relation between flow and velocity of a fluid is given by:

Q=Av

where:

  • Q, flow [ft3/s]
  • A, cross section of the pipe [ft2]
  • v, velocity of the fluid [ft/s]

1)

To convert our data to appropiate units, we use the following convertion factors:

1 ft=12 inches

1 ft3=7,48 gallons

1 minute=60 seconds

So,

Q=\frac{3,60 gallons}{1 min}*\frac{1min}{60 s}*\frac{1ft3}{7,48gallons}=0,00802 \frac{ft3}{s}

As the pipe has a circular section, we use A=πd^2/4:

d=4,26 inch *\frac{1ft}{12 inch}=0,355ft\\  A=\pi \frac{0,355^{2} }{4}=0,0989ft2

Finally:

Q=vA......................v=Q/A

v=\frac{0,00802ft^{3} /s}{0,0989ft^{2} }=0,081ft/s

2)

The following formula is used to calculate the specific gravity of a material:

SG = ρ / ρW  

where:

  • SG = specific gravity,
  • ρ = density of the material [lb/ft3]
  • ρW = density of water [lb/ft3] = 62.4 lbs/ft3

then:

ρ = SG*ρW   = 1,49* 62,4 lb/ft3 = 93 lb/ft3

To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume:

0,00802 \frac{ft3}{s}*\frac{93lb}{1ft3}=0,746lb/s

7 0
3 years ago
An excess of mg(s) is added to 100.ml of 0.400 m hcl. at 0c and 1 atm pressure, what volume of h 2 (g) can be obtained?
ra1l [238]
The balanced equation for the reaction between Mg and HCl is as follows
Mg + 2HCl --> MgCl₂ + H₂
stoichiometry of HCl to H₂ is 2:1

number of HCl moles reacted - 0.400 mol/L x 0.100 L = 0.04 mol of HCl
since Mg is in excess HCl is the limiting reactant 
number of H₂ moles formed - 0.04/2 = 0.02 mol of H₂

we can use ideal gas law equation to find the volume of H₂
PV = nRT 
where 
P - pressure - 1 atm x 101 325 Pa/atm = 101 325 Pa
V - volume
n - number of moles - 0.02 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 0 °C + 273 = 273 K
substituting these values in the equation 

101 325 Pa x V = 0.02 mol x 8.314 Jmol⁻¹K⁻¹ x 273 K
V = 448 x 10⁻⁶ m³
V = 448 mL 
therefore answer is 
c. 448 mL 
5 0
3 years ago
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