A1, a1r 1, a1r 2, a1r 3, a1r 4, .... a1r n-1 is the general formula for the Sum of a what?
1 answer:
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Answer:
see attached
Step-by-step explanation:
The equation is in the form ...
4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance
Comparing this to your equation, we see ...
p = 4, (h, k) = (3, 4)
p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...
vertex: (3, 4)
axis of symmetry: x = 3
focus: (3, 8) . . . . . 4 units up from vertex
directrix: y = 0 . . . horizontal line 4 units down from vertex
Answer:
g(x)<j(x)<k(x)<f(x)<m(x)<h(x)
Step-by-step explanation:
1.
The denominator of f is defined for all real values of x
Therefore, the function is continuous on the set of real numbers
3.
It cannot be factorize .
Therefore, it has no real values for which it is not defined .
Hence, function h is defined for all real values.
2.
The denominator of g is defined for all real values of x.
Therefore, the function g is continuous on the set of real numbers
4.
x-9=0
x=9
The function i is not defined for x=9
Therefore, the function i is not continuous on the set of real numbers.
5.
The denominator of j is defined for all real values of x.
Therefore, the function j is continuous on the set of real numbers.
6.
It cannot be factorize .
Therefore, it has no real values for which it is not defined .
Hence, function k is defined for all real values.
7.
The function is not defined for x=8 and x=1
Hence, function l is not defined for all real values.
8.
The denominator of m is defined for all real values of x.
Therefore, the function m is continuous on the set of real numbers.
g(x)<j(x)<k(x)<f(x)<m(x)<h(x)