Define the axis of symmetry, vertex, focus and directrix for
1 answer:
Answer:
see attached
Step-by-step explanation:
The equation is in the form ...
4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance
Comparing this to your equation, we see ...
p = 4, (h, k) = (3, 4)
p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...
vertex: (3, 4)
axis of symmetry: x = 3
focus: (3, 8) . . . . . 4 units up from vertex
directrix: y = 0 . . . horizontal line 4 units down from vertex
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Answer:
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Step-by-step explanation:
We use casework on when and when
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For the first case, , we add 9 to both sides to get
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Dividing both sides by 3 gives
For the second case, , we add 9 to both sides to get
.
Dividing both sides by 3 gives
.
Checking both cases, we plug in and
.
For the first case, we have , which satisfies the equation.
For the second case, we have , which also satisfies the equation.
This gives us two solutions to the equation; and
.