Question

Define the axis of symmetry, vertex, focus and directrix for

Answer 1

Answer:

  see attached

Step-by-step explanation:

The equation is in the form ...

  4p(y -k) = (x -h)^2 . . . . . (h, k) is the vertex; p is the focus-vertex distance

Comparing this to your equation, we see ...

  p = 4, (h, k) = (3, 4)

p > 0, so the parabola opens upward. The vertex is on the axis of symmetry. That axis has the equation x=x-coordinate of vertex. This tells you ...

  vertex: (3, 4)

  axis of symmetry: x = 3

  focus: (3, 8) . . . . . 4 units up from vertex

  directrix: y = 0 . . . horizontal line 4 units down from vertex