Answer:
The teacher should divide the amount of students by 5, that way they'll find how many groups they'll have. And the amount of groups they'll have is 6 groups of 5 students, you didn't ask for this part but I decided it'd be best to add it. Hope this helps, have an amazing day you awesome human! ^w^
Step-by-step explanation:
Answer:
Logic with the use of Truth Table
Step-by-step explanation: a) Oleg is a math major= P; Oleg is a economic major=Q; Oleg is required to take math 362=R; Oleg is not required to take 362=←R
b)i) Oleg is a math major or Oleg is an economic major:
P║ Q ║ P∨Q
T T T
T F T
F T T
F F F
ii) Oleg is a math major, then Oleg is required to take Math 362:
P║ R ║ P∧ R
T T T
T F F
F T F
F F F
iii) Oleg is an economic major or Oleg is not required to take Math 362:
Q║ ←R ║ Q ∨ ←R
T T T
T F T
F T T
F F F
c) It is valid because Oleg can only take Math 362 since Oleg is a math major, therefore, it follows that, R ∧ ( P ∨ Q) is valid.
Answer:
Irrational numbers
Step-by-step explanation:
Any irrational number plus a rational number like (5/8) creates another irrational number.
How many four element subsets of \{1, 2, 3, 4, 5, 6, 7\}{1,2,3,4,5,6,7} have 11 as an element but do not have 77 as an element
levacccp [35]
If we fix 1 to be an element of a subset of size 4, then we can choose from 5 other elements (2, 3, 4, 5, and 6) to fill the other 3 spots in the subset. So there are
such subsets.
Correct answer is going to be D
