Not sure, but the areas of a triangle is BH/2 so the dimensions should be 8 and 6 then 10.
8 x 6 = 48
48/2 = 24
Maybe that can help with the equation
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
2x - 5y = 20
At the x-intercept, y=0 .
2x = 20 ==> x = 10
At the y-intercept, x=0.
-5y = 20 ==> y = -4
Answer:
D.
Step-by-step explanation:
if he divides (7/8) / (2/5)
he will get x bottles of honey if each bottle weighs 2/5 pound
1. 7 hours and 40 min
2. 1 hour and 24 min
3. 4 hours and 45 min
4. 8 hours and 48 min
