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sergiy2304 [10]
3 years ago
7

A boat travels with velocity vector (25, 25 StartRoot 3 EndRoot). What is the directional bearing of the boat?

Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

A on Egde

Step-by-step explanation:

i got it right

iogann1982 [59]3 years ago
6 0

Answer:

The directional earing is N 30° E

Step-by-step explanation:

The given velocity vector is (25, 25·√3), therefor, we have;

R = 25·i + 25·√3·j

The angle of inclination of the direction of the boat with the horizontal = Arctan (y/x)

Where;

(x, y) = The coordinate of the components of the velocity of the boat

Therefore;

Arctan (y/x)  =  Arctan (25·√3/25) = Arctan (√3) = 60° North of East

The directional bearing which is the bearing relative to the northern direction is given as follows;

The directional earing = 90° - 60° = N 30° E.

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<h3>How can the type of a given triangle be found?</h3>

Taking the vertices of ∆ABC as found in a similar question online as A(-1, 3), B(-5, -1), C(3, -1), calculating the lengths of the sides of the triangle gives;

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