Question

A boat travels with velocity vector (25, 25 StartRoot 3 EndRoot). What is the directional bearing of the boat?

Answer 1

Answer:

A on Egde

Step-by-step explanation:

i got it right

Answer 2

Answer:

The directional earing is N 30° E

Step-by-step explanation:

The given velocity vector is (25, 25·√3), therefor, we have;

R = 25·i + 25·√3·j

The angle of inclination of the direction of the boat with the horizontal = Arctan (y/x)

Where;

(x, y) = The coordinate of the components of the velocity of the boat

Therefore;

Arctan (y/x)  =  Arctan (25·√3/25) = Arctan (√3) = 60° North of East

The directional bearing which is the bearing relative to the northern direction is given as follows;

The directional earing = 90° - 60° = N 30° E.