Which of the following is written as a rational function?

Winter temperatures tend to be cold in the city of Johnstown. The table of values represents the temperature of Johnstown during

trapecia [35]

Answer:

Part A Part B Part C explained

Step-by-step explanation:

PART A: Extrema: relative minimums (4,-2) and maybe (7,-3) (uncertain because it’s an endpoint), relative maximums (6,0) and maybe (1,6) (uncertain because it’s an endpoint)

Zeros: (6,0), somewhere between t = 3 and t = 4 since the graph changes from positive to negative, and somewhere possibly between t = 6 and t = 7 unless the graph hits (6,0) and stays negative.

End behavior: We can guess that as x approaches infinity, the functions approaches negative infinity, and as x approaches negative infinity, the function approaches infinity.

Intervals of increase and decrease: Increasing on (4, 6), decreasing on (1, 4) and (6, 7)

PART B: The relative minimums indicate that the two lowest temperatures occurred on day 4 at -2°F and day 7 at -3°F. The relative maximums indicate that the weekly highs were day 1 at 6°F and day 6 at 0°F.

The zeros of the function represent when the temperature in Johnstown was 0°F. This happened sometime between days 3 and 4 and on day 6.

In the context of the problem, it doesn’t make sense to go an infinite number of degrees below zero. And, the end behavior is ignored because of the restricted range.

The intervals of increase indicate when the temperature is rising, and the intervals of decrease indicate when the temperature is dropping. The intervals where the values are positive indicate when the temperature is above 0°F. The intervals where the values are negative indicate when the temperature is below 0°F.

PART C: The domain is restricted to the number of days the town recorded the temperature. So, the domain is [1, 7].

The range represents the range of temperatures of Johnstown over the course of one week. So, the range is [-3, 6].

6 0

2 years ago

Miguel volunteers at a library. He needs to arrange 576 books on shelves for a book sale. There are 16 empty shelves. Miguel put

Sergeeva-Olga [200]

Answer:

The equal number of books that is arranged on 16 empty shelves is 36 .

Step-by-step explanation:

Given as :

The total number of books Miguel need to arrange = 576

The total number of empty shelves = 16

Let The total number of books arrange on each shelves = x

So , According to question

The total number of books Miguel need to arrange = The total number of empty shelves × The total number of books arrange on each shelves

I.e 576 = 16 × x

Or, x = $\frac{576}{16}$

∴ x = 36

Hence The equal number of books that is arranged on 16 empty shelves is 36 . Answer

6 0

3 years ago

Problem 9

lapo4ka [179]

Answer:

3:36PM

Step-by-step explanation:

Leon starts at 12PM with 12 gallons of gas, and after 2 hours he has used 5 gallons of gas. This means that every 2 hours he uses 5 gallons of gas.

Next we will find at what point Leon will stop to get gas. Since he will stop when the tank is at $\frac{1}{4}$ capacity, we can use the equation:

$\frac{1}{4} * 12 = \boxed{3}$

This shows $\frac{1}{4}$ of his tank's capacity ( $12$ ) is equal to $3$ gallons. This means he will stop for gas when $3$ gallons are remaining.

Now we need to find how many gallons of gas he uses, but as a unit rate. (This will allow us to find what time Leon will stop to get gas.) To find the unit rate, we will need to find how many gallons of gas he uses per hour.

$\frac{\mbox{5 gallons}}{\mbox{2 hours}} = \frac{\mbox{2.5 gallons}}{\mbox{1 hours}}$

This is a simple proportion, and now we know he uses $2.5$ gallons of gas per hour.

Now we can how many hours of gas Leon has left.

He has $7$ gallons of gas left at 2PM, so we can divide to find how many hours left of gas he has.

$\frac{7-3}{2.5} = 1.6$

The $7-3$ is because Leon doesn't stop when his tank is empty, he stops $3$ gallons earlier. We are dividing by $2.5$ because that is how much gas he uses per hour, meaning the result of this division ( $1.6$ ) is how many hours he has left.