A 15 foot ladder is leaning against a wall. if the foot of the ladder is sliding away from the wall at a rate of 10 ft/sec, at w
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Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is
Using this formula, we get
and
Now, area of the quadrilateral is
Therefore, the area of the quadrilateral is 34 cm².
Answer:
11) x = 11
12) x = 11
Step-by-step explanation:
11) Δ RQP and Δ RLK are similar.
Hence, the ratios of the corresponding sides of the two triangles will be constant.
So,
⇒
⇒
⇒ x - 4 = 7
⇒ x = 11 (Answer)
12) Δ QRS and Δ QDC are similar.
So,
⇒
⇒ 2x - 14 = 8
⇒ 2x = 22
⇒ x = 11 (Answer)