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mihalych1998 [28]
2 years ago
13

James invested $4,000 at 5% interest per year; how long will it take him to earn $200 in simple interest?

Mathematics
2 answers:
sweet-ann [11.9K]2 years ago
4 0
<h3>Given :</h3>

  • Principal, P = $ 4,000
  • Rate, R = 5 %
  • Interest Amount, I = $ 200

<h3>To Find :</h3>

  • Time, T = ?

<h3>Solution :</h3>

We, know that :

\underline{\boxed{\sf Interest \: amount = \dfrac{Principal \times Rate \times Time}{100}}}

\underline{\boxed{\sf I = \dfrac{P \times R \times T}{100}}}

By putting values, we have

\sf : \implies 200 = \dfrac{4000 \times 5 \times T}{100}

\sf : \implies 200 \times 100 = 20000  \times T

\sf : \implies 20000 = 20000  \times T

\sf : \implies \cancel{\dfrac{20000}{20000}} = T

\sf : \implies 1 = T

\underline{\boxed{\sf T = 1 \: year}}

It takes 1 year for him to earn $ 200 in simple interest.

tester [92]2 years ago
3 0

Answer:

It takes 1 year.

Step-by-step explanation:

You have to apply simple interest formula, I = (P×R×T)/100 where I represent interest amount, P is principle, R is interest rate and T is number of years :

I =  \frac{PRT}{100}

200 =  \frac{4000 \times 5 \times T}{100}

20000 = 20000T

T = 1

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This question was not written properly

Complete Question

Steve has 54 stamps in his collection of 13 cent, 29 cent, and 45 cent stamps, totaling a value of $15.98. If the number of 13 cent stamps is doubled, the new total value of his stamp collection would be $17.80. Find the number of each type of stamp in his collection.

Answer:

a) The number of 13 cent = 14

b) The number of 29 cent = 24

c) The number of 45 cent = 16

Step-by-step explanation:

We are told he has 54 stamps in total.

These stamps are;13 cent, 29 cent, and 45 cent stamps.

Let's

Number of 13 cent = a

Number of 29 cent = b

Number of 45 cent = c

Hence,

a + b + c = 54........... Equation 1

The total value of the 3 stamps are $15.98.

1 cent = $0.01

We have

0.13a + 0.29b + 0.45c= $15.98 ......... Equation 2

We know from the question that:

13 cent stamps is doubled, the new total value of his stamp collection would be $17.80.

Therefore

2(0.13a) + 0.29b + 0.45c = 17.8

0.26a + 0.29b + 0.45c = 17.8 ......... Equation 3

Combining Equation 2 and 3 together

0.13a + 0.29b + 0.45c= 15.98 ......... Equation 2

0.26a + 0.29b + 0.45c = 17.8 ......... Equation 3

We eliminate b and c by Subtracting Equation 3 from 3

0.13a = 1.82

a = 1.82/0.13

a = 14

a + b + c = 54........... Equation 1

Since a = 14

14 + b + c = 54

b + c = 54 - 14

b + c = 40

c = 40 - b

Substitute 40 - b for c and 14 for a is Equation 2

0.13a + 0.29b + 0.45c= 15.98 ......... Equation 2

0.13(14 ) + 0.29b + 0.45(40 - b) = 15.98

= 1.82 + 0.29b + 18 - 0.45b = 15.98

Collect like terms

1.82 + 18 - 15.98 = 0.45b - 0.29b

3.84 = 0.16b

b = 3.84/0.16

b = 24

Hence: Solving for c

a + b + c = 54........... Equation 1

14 + 24 + c = 54

38 + c = 54

c = 54 - 38

c = 16

Therefore,

The number of 13 cent = 14

The number of 29 cent = 24

The number of 45 cent = 16

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