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3 years ago

Count by ones from 368 to 500 change fot a larger unit when necessary

Mathematics

1 answer:

kykrilka [37]3 years ago

6 0

368+100=468

500-468=92. So,start with 368 then add 100 which is 468,then add 92 which is finally 500

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Plz help<br> and explain

vovikov84 [41]

To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.

We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.

The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.

Therefore
Area of band
$=(x+10)^2-x^2$ [recall $(a+b)^2=a^2+2ab+b^2$
$=x^2+20x+100-x^2$
$=20x+100$ or 20(x+5) if you wish.

8 0

3 years ago

Find the interquartile range of the data.

likoan [24]

The answer is 14. Here is how I work it out.

First we are going have to identify quartile 1 and quartile 3.

So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.

31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)

For the next step we have to find the median of each group.

(31,33,35,41,43,)|(46,48,49,49,50)

The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.

Now subtract quartile 1 from quartile 3.

49 – 35 = 14

So the interquartile range of this data set is 14.

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7Dx%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20-1" id="TexFormula1" title="\frac{2

egoroff_w [7]

$\large \mathfrak{Solution : }$

let's solve for x :

$\dfrac{2}{9} x - \dfrac{1}{3} = - 1$

$\dfrac{2}{9} x = - 1 + \dfrac{1}{3}$

$\dfrac{2}{9} x = \dfrac{ - 3 + 1}{3}$

$x = \dfrac{ - 2}{3} \times \dfrac{9}{2}$

$x = - 3$

I hope it helped...

7 0

2 years ago

Read 2 more answers

A doctor orders 20 grams of a 52% solution of a certain medicine. The pharmacist has only bottles of 40% solution and bottles of

Anvisha [2.4K]

Try, please, this:
1) Imagine, that pharmacist used 'x' gr. of 40% solution and 'y' of 70% solution.
Together (20 gr. of 52% sol.) it will be x+y=20.
2) From other side, the pharmacist combined 40x and 70y gramms, after obtaining together it is 52(x+y) gramms. In other words 40x+70y=52(x+y)
3)
$\left \{ {{x+y=20} \atop {40x+70y=52(x+y)}} \right. \ =\ \textgreater \ \ \left \{ {{y=8} \atop {x=12}} \right.$
Answer: 8 gr. of 70% solution and 12 gr. of 40%.

4 0

3 years ago

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Help on math homework

Tasya [4]

I believe these are the answers but I’m not sure about letter A

3 0

3 years ago