From the information given, the rotated triangle is same as the original triangle. This is because, vertices of the rotation remain at the origin - (0,0).
<h3>What is the proof the above?</h3>
Notice that the question states: △A'B'C' is the image of △ABC. Given that the △ without primes is the original and the one with primes depict the rotated triangle,
under a rotation about the origin, (0,0) (0,0) (0, 0), indicating no movement,
△A'B'C' is in the same position with △ABC.
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Answer:
<em>Sorry, If this late but here's the answer. The data plots represent the hours students study each week in two different classrooms. The mean number of hours a student in Mr. Hart’s class studies is </em><em>4.6</em><em> hours. The mean number of hours a student in Ms. Perry’s class studies is </em><em>2.8</em><em> hours. A typical student in Mr. Hart’s class studies </em><em>More than</em><em> a typical student in Ms. Perry’s class. </em><em>Good Luck!</em>
<em>Here's the photo... </em>
If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
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Answer:
Step-by-step explanation:
Exponential function represents as x^2 = x * x or 2^3 = 2*2*2 etc.
As per options,
(A) We are unable to write the number 79 as a exponent.
B) We are unbale to write the number 742 as a exponent as well.
(c) We are unable to write the number 73 as a exponent as well.
(d) We are able to write the number 79.79 as exponent (79)^2. Base is 79 and exponent is 2 and it is single exponential expression as base is only one number.
