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Nata [24]
3 years ago
5

The difference of x and 9 is at the most 25

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0
I ain’t never seen two pretty best friends
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35 + 70 = 35(1 + 2)<br> O Yes<br> O No
Sliva [168]

Answer:

Yes

Step-by-step explanation:

Because 35 * 1 is 35 and 35 * 2 is 70

6 0
4 years ago
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51 divided by 4539 answer
Free_Kalibri [48]

Answer:

51/4539=.01123596

4539/51=89

Step-by-step explanation:

6 0
3 years ago
Can someone help me please?
morpeh [17]
Heya bro!!

------------------------------------

If uh r asking about scientific notification then x must be in lowest form but decimal point is after 1.

So correct answer is 1.04 * 10^2 .

If uh wanna check multiply it.. Uh will get 104.

Hope it helps uh!
5 0
3 years ago
Steps factoring polynomials using gcf for 9x²+9x
Molodets [167]

Answer:

Step-by-step explanation:

Step 1: Identify the GCF of the polynomial.

Step 2: Divide the GCF out of every term of the polynomial. ...

Step 1: Identify the GCF of the polynomial. ...

Step 2: Divide the GCF out of every term of the polynomial.

Step 1: Identify the GCF of the polynomial. ...

Step 2: Divide the GCF out of every term of the polynomial .

6 0
3 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
3 years ago
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