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Zanzabum
3 years ago
15

Leslie is 5 times Rebecca's age . In 2 years, Leslie will be 3 times Rebecca's age How old is Rebecca now?

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
Rebecca was 2 at first, but 2 years later she is 4. Leslie was 10 at first, but 2 years later she is 12. 12 is 3 times greater than 4.

Please vote my answer brainliest! Thanks.
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What inverse operation should be used to isolate the variable in the equation c ÷ 7 = 2?
Kobotan [32]

Answer:

C = 14

Step-by-step explanation:

14*7= 2

5 0
3 years ago
How to integrate 1/(1-y)^2
Akimi4 [234]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/866966

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy}\\\\\\ =\mathsf{\displaystyle\int\!\dfrac{-1}{(1-y)^2}\cdot (-1)\,dy}\\\\\\ =\mathsf{\displaystyle- \int\!(1-y)^{-2}\cdot (-1)\,dy\qquad\quad(i)}


Substitution:

\begin{array}{lcl} \mathsf{1-y=u}&\quad\Rightarrow\quad&\mathsf{y=1-u}\\\\ &&\mathsf{dy=-1\,du} \end{array}


So the integral \mathsf{(i)} becomes

=\mathsf{\displaystyle -\int\! u^{-2}\,du}\\\\\\ =\mathsf{-\,\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\ =\mathsf{-\,\dfrac{u^{-1}}{-1}+C}\\\\\\ =\mathsf{u^{-1}+C}\\\\\\ =\mathsf{\dfrac{1}{u}+C}

=\mathsf{\dfrac{1}{1-y}+C}\\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy=\dfrac{1}{1-y}+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral fraction rational substitution power differential calculus</em>

3 0
2 years ago
Aleka and Helene both opened savings accounts that earn 2.5% interest a year. Aleka puts $2,500 into her account. Helene put $1,
Xelga [282]

Given:

Amount in Aleka and Helene accounts represented by the following function:

Aleka: f(x) = 2500(1.025)^x

Helene: g(x) = 1500(1.025)^x + 200x

To find:

The function represents the difference, h(x) = f(x) -g(x), between the value of Aleka's and Helene's total savings after x years.

Solution:

We have,

f(x) = 2500(1.025)^x

g(x) = 1500(1.025)^x + 200x

Now,

h(x) = f(x)-g(x)

h(x) = 2500(1.025)^x-[1500(1.025)^x + 200x]

h(x) = 2500(1.025)^x-1500(1.025)^x - 200x

h(x) = 1000(1.025)^x - 200x

Therefore, the correct option is C.

8 0
3 years ago
Two consecutive integers have a sum of 53. Find the integers.
Flura [38]

Answer:

give brainliest please I need it to level up

Step-by-step explanation:

Let one of the numbers be x,

Then the two numbers are x and x +1

And,

x+x+1 = 53

2x = 53 - 1 (Transposing 1 from LHS to RHS)

2x = 52

x = 52/2

x = 26

x + 1 = 27

So, The two numbers are 26 and 27.

7 0
2 years ago
A. 10<br> b. 36<br> c. 40 <br> d. 20
8090 [49]
Yes photo math!!!!!!! It will save your life
8 0
2 years ago
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