Based on the model, approximately how many customers will be on the restaurant when there are 10 cars parked in the restaurant’s
1 answer:
Answer:
23
Step-by-step explanation:
From the graph, derive the best fit equation :
Using the points ;
(0,2.5) (100 ,35)
x1 = 0 ; y1 = 2.5 ; x2 = 100 ; y2 = 35
Slope formula, m = (y2-y1)/(x2-x1)
m = (35-2.5)/(100-0)
m= (32.5)/100
m = 0.325
The y intercept, value on the graph where best fit line crosses the y axis = 2.5
The equation :
y = mx + c
c = intercept ; m = slope
y = 0.325x + 2.5
y = Number of cars
x = number of customers
The number of customers if there are 10 cars parked :
10 = 0.325x + 2.5
10 - 2.5 = 0.325x
7.5 = 0.325x
x = 7.5 / 0.325
x = 23.076
x = 23
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Answer:
Step-by-step explanation:
Lets divide it in cases, then sum everything
Case (1): All 5 numbers are different
In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.
The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.
Case (2): 4 numbers are different
We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4
We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.
The total cardinality of this case is
Case (3): 3 numbers are different
As we did before, we pick 3 elements from a set of n. The amount of possibilities is
Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of
Case (4): 2 numbers are different
We pick 2 numbers from a set of n, with a total of possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.
The total amount of possibilities for this case is
Case (5): All numbers are the same
This is easy, he have as many possibilities as numbers the set has. In other words, n
Conclussion
By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is
I hope that works for you!