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melamori03 [73]

2 years ago

9

Three-fourths of the fish in Gary's fish tank are guppies. One-sixth of the guppies are red. What fraction of the fish in Gary's

tank are red guppies?

1 answer:

VladimirAG [237]2 years ago

5 0

Answer:

2/12 of the guppies are red. I think I understand your question. I apologize if it's incorrect.

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A bike was originally 240.00 the price was marked up 15%.what is the new price of the bike

Law Incorporation [45]

Answer:

276

Step-by-step explanation:

240+(240*.15) = 276

7 0

3 years ago

Please help!!!! I need it quick!!!!

alukav5142 [94]

Answer:

f(4) = 49

f(-3) = -35

Step-by-step explanation:

f(4) = 12(4) + 1 = 48 + 1 = 49

f(-3) = 12(-3) + 1 = -36 + 1 = -35

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2 years ago

What does a sample space look like?

grin007 [14]

Answer:

A sample space is a collection or a set of possible outcomes of a random experiment. The sample space is represented using the symbol, “S”. The subset of possible outcomes of an experiment is called events. A sample space may contain a number of outcomes that depends on the experiment

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6 0

1 year ago

Read 2 more answers

Evaluate the following expression. [4 + (12 - 2) ÷ 5] ÷ 7

Anika [276]

Answer:

[4 + (12 - 2) ÷ 5] ÷ 7

[4 + 6 / 5] / 7

[10 / 5] / 7

2 / 7

= 2/7 or 0.28571428571

7 0

2 years ago

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A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i

lutik1710 [3]

Answer: $1-(\frac{364}{365})^n$

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^x$ , where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

$p=\dfrac{1}{365}$

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

$P(x\geq1)=1-P(x$

Hence, the probability there is at least one day in a year when nobody has a birthday = $1-(\frac{364}{365})^n$

5 0

3 years ago